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coldgirl [10]
3 years ago
9

Paz has $18 in her wallet. This is 3 times the money in her pocket. Write and solve an equation to find how much money Paz has i

n her pocket.
Mathematics
2 answers:
algol133 years ago
4 0

3x=18

x= 6

6 dollars in pocket

My name is Ann [436]3 years ago
4 0

Answer:

32+s=55

Step-by-step explanation:

Sarah is saving money to buy a jacket that costs $47. She has already saved $25. Write an equation to find out how much more money Sarah needs to save, using x, to represent how much more she needs to save.

You might be interested in
2/9 of the members are boys in a community service club. if there are 95 more girls than boys, how many girls are there in club?
Talja [164]

Answer:

There are 171 members in the club

Number of boys = 38

Number of girls = 133

Step-by-step explanation:

Let

x = total members of the club

Boys = 2/9x

if there are 95 more girls than boys

Girls = 2/9x + 95

how many girls are there in club?

Total members in the club = boys + girls

x = 2/9x + 2/9x + 95

x = 2+2/9x + 95

x = 4/9x + 95

x - 4/9x = 95

9x-4x/9 = 95

5/9x = 95

Divide both sides by 5/9

x = 95 ÷ 5/9

= 95 × 9/5

= 855/5

= 171

boys = 2/9x

= 2/9 * 171

= 342 / 9

= 38

Girls = 2/9x + 95

= 38 + 95

= 133

Total = 38 + 133

= 171

There are 171 members in the club

Number of boys = 38

Number of girls = 133

5 0
3 years ago
5.
Paha777 [63]

Step-by-step explanation:

30 minutes x an hour and half past prolly around 1 hr and 30 sec

5 0
3 years ago
CAN ANYONE TELL ME WHAT THE ANWSER IS:
Anna71 [15]
2.8 I got that same on on khan academy it’s 2.8 trust me
7 0
2 years ago
Determine determine whether the following geometric series converges or diverges. if the series converges find its sum.
Lilit [14]

For starters,

\dfrac{3^k}{4^{k+2}}=\dfrac{3^k}{4^24^k}=\dfrac1{16}\left(\dfrac34\right)^k

Consider the nth partial sum, denoted by S_n:

S_n=\dfrac1{16}\left(\dfrac34\right)+\dfrac1{16}\left(\dfrac34\right)^2+\dfrac1{16}\left(\dfrac34\right)^3+\cdots+\dfrac1{16}\left(\dfrac34\right)^n

Multiply both sides by \frac34:

\dfrac34S_n=\dfrac1{16}\left(\dfrac34\right)^2+\dfrac1{16}\left(\dfrac34\right)^3+\dfrac1{16}\left(\dfrac34\right)^4+\cdots+\dfrac1{16}\left(\dfrac34\right)^{n+1}

Subtract S_n from this:

\dfrac34S_n-S_n=\dfrac1{16}\left(\dfrac34\right)^{n+1}-\dfrac1{16}\left(\dfrac34\right)

Solve for S_n:

-\dfrac14S_n=\dfrac3{64}\left(\left(\dfrac34\right)^n-1\right)

S_n=\dfrac3{16}\left(1-\left(\dfrac34\right)^n\right)

Now as n\to\infty, the exponential term will converge to 0, since r^n\to0 if 0. This leaves us with

\displaystyle\lim_{n\to\infty}S_n=\lim_{n\to\infty}\sum_{k=1}^n\frac{3^k}{4^{k+2}}=\sum_{k=1}^\infty\frac{3^k}{4^{k+2}}=\frac3{16}

8 0
3 years ago
Read 2 more answers
An ordered pair that makes a linear equation true is called a?
pav-90 [236]

Answer:

the solution of the equation.

Step-by-step explanation:

8 0
2 years ago
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