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elena-14-01-66 [18.8K]
3 years ago
7

True/ False: a sample of 100 fuses from a very large shipment is found to have 10 that are defective. The 95% confidence interva

l would indicate that, the propotion of defective fuses is between 0 and 0.28.
Mathematics
1 answer:
Kobotan [32]3 years ago
3 0

Answer:

False

Step-by-step explanation:

These questions depend on sample size, which in this case, it'd not fall between 0 and .28.

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Find the complex fourth roots \[-\sqrt{3}+\iota \] in polar form.
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Let z=-\sqrt3+i. Then

|z|=\sqrt{(-\sqrt3)^2+1^2}=2

z lies in the second quadrant, so

\arg z=\pi+\tan^{-1}\left(-\dfrac1{\sqrt3}\right)=\dfrac{5\pi}6

So we have

z=2e^{i5\pi/6}

and the fourth roots of z are

2^{1/4}e^{i(5\pi/6+k\pi)/4}

where k\in\{0,1,2,3\}. In particular, they are

2^{1/4}e^{i(5\pi/6)/4}=2^{1/4}e^{i5\pi/24}

2^{1/4}e^{i(5\pi/6+2\pi)/4}=2^{1/4}e^{i17\pi/24}

2^{1/4}e^{i(5\pi/6+4\pi)/4}=2^{1/4}e^{i29\pi/24}

2^{1/4}e^{i(5\pi/6+6\pi)/4}=2^{1/4}e^{i41\pi/24}

7 0
3 years ago
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Daniel [21]
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6 0
3 years ago
Use the table to identify the value of p and q that should be used to factor x^2-3x-10 as (x+p)(x+q) I’ve seen the answer with p
Elza [17]

Answer:

1

Step-by-step explanation:

1 is the right answer for this question

3 0
3 years ago
Find the intersection point between the lines of equations:<br><br>2x-y+6=0 and 2x+3y-6=0 ​
Ugo [173]

Step-by-step explanation:

The two equation will intersect each other at the point which will be the solution of the given two equations , and the given equations are ,

\implies 2x -y +6=0\\\\\implies 2x + 3y -6=0

On subtracting the given equations we have,

\implies -y - 3y +6 -(-6) = 0 \\\\\implies -4y = -12 \\\\\implies y = -12/-4\\\\\implies y = 3

Put this value in any equation , we have ,

\implies 2x -3 +6 =0\\\\\implies 2x = -3 \\\\\implies x =\dfrac{-3}{2} \\\\\implies x =-1.5

Hence the lines will Intersect at ,

\implies\underline{\underline{ Point=(-1.5, 3)}}

8 0
2 years ago
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Graph this function: f(x)=x2-4x-5
Maksim231197 [3]
A would be 1 as b would be -4

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3 years ago
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