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Morgarella [4.7K]
3 years ago
12

Let f(x)=11-3xm compute f(2)+f^-1(2)

Mathematics
1 answer:
Ganezh [65]3 years ago
8 0
Taking f(X) to be y
Y = 11 - 3X
3X = 11 - y
X  = (11-y)÷3
F^-1(x) = (11 - x)÷3 addING both equations
It gives = 0

Please mark as brainliest
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Answer:

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Step-by-step explanation:

Let's write -2x+4y=8 to slope-intercept form.

We do this by solving for y

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Add 2x to both sides

4y=8+2x

Divide both sides by 4

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Now that we have that equation in slope-intercept form, the question wants us to find a line that is parallel to it that passes the point (-5, -1).

A line is parallel to another line is they have the same exact slope.

The slope is \frac{1}{2}.

Slope-intercept form: y=mx+b, where m is the slope and b is the y-intercept.

So, let's see what we have here so far.

y=\frac{1}{2}x +b

All we have to do is find b.

The question wants the line to pass the point (-5, -1).

Let's plug that point in.

-1=\frac{1}{2} (-5)+b\\-1=\frac{-5}{2}+b\\\frac{3}{2} =b\\

We have all the information needed to finish this problem!

So, the line that is parallel to -2x+4y=8 and passes through the point (-5, -1).

y=\frac{1}{2}x+\frac{3}{2}

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Answer:

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Step-by-step explanation:

The point-slope form of the equation for a line can be written as ...

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