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Naddika [18.5K]
3 years ago
13

Which choice does not name a chord of circle F?

Mathematics
2 answers:
inn [45]3 years ago
8 0

Answer:

<h2>A. FE</h2>

Step-by-step explanation:

In geometry, a chord is defined as any line that joins two points of the circumference.

So, in the given graph we have that AC, AB, EB are chords, because they joint two points of the circumference.

On the other hand, FE, FD, FC, FA, FB are not chords, because they only joint a point on the circumference with the center, so they represent the radius.

Therefore, among the options A. FE doesn't represent a chord.

andreyandreev [35.5K]3 years ago
4 0
A, FE as a chord is a straight line that goes from one end of the circle to another end. This means both ends of the line should touch the circumference. In FE, only one end of the line is touching the circumference. The other isn't. There FE isn't a chord for circle F
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2 years ago
Consider the following sets of matrices: M2(R) is the set of all 2 x 2 real matrices; GL2(R) is the subset of M2(R) with non-zer
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Answer:

Step-by-step explanation:

REcall the following definition of induced operation.

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Case SL2(R):

Let A,B matrices in SL2(R). Then, det(A) and det(B) is different from zero. So

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So AB is also in SL2(R).

Case GL2(R):

Let A,B matrices in GL2(R). Then, det(A)= det(B)=1 is different from zero. So

\text{det(AB)} = \text{det}(A)\text{det}(B)=1\cdot 1 = 1.

So AB is also in GL2(R).

With these, we have proved that the matrix multiplication over SL2(R) and GL2(R) is an induced operation from the matrix multiplication over M2(R).

7 0
3 years ago
How many 1/4 cups goes into 2 2/4 cups
Serhud [2]
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7 0
2 years ago
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