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erastova [34]
3 years ago
11

A woman puts $1 million dollars into a savings account that she is not going to touch. She isn’t going to work either but she wi

ll live off the interest. If the rate of interest on the account is 6 1/2% what is the amount she will make in interest? If her totally expenses last year is $47,000 will she be able to live off the interest? Justify your answer
Mathematics
1 answer:
Triss [41]3 years ago
6 0

Answer:

i. The amount made in interest is $65,000.

ii. Yes, because her expenses is lesser that her interest.

Step-by-step explanation:

i. The woman puts $1,000,000 in a savings account with an interest rate of 6\frac{1}{2}%.

Interest rate = 6\frac{1}{2}% = \frac{13}{200}

The amount she would make in interest = \frac{13}{200} × 1,000,000

                                                                   = 65,000

The amount made in interest is $65,000.

ii. The total of her expenses last year is $47,0000 which is lesser than the amount made in inerest.

After her total expenses, should would have a remainder of;

                                   = $65,000 - $47,0000

                                  = $18,000

Therefore, she would be able to live off the interest.

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Goryan [66]

The number of people which gets 1/6 of the pizza as required for lunch the next day is; 4 persons.

<h3>What is the number of people who get 1/6 of the pizza for lunch?</h3>

It follows from the task content that only 4/6 of the pizza is left and each individual needs 1/6 of the pizza for lunch.

On this note, the 4/6 fraction of pizza left mean: 4 × 1/6.

Therefore, only four persons get lunch.

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Consider the vector x: x &lt;- c(2, 43, 27, 96, 18) Match the following outputs to the function which produces that output. Opti
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<u>Completed Question</u>

Outputs to be matched to the functions are:

  • 1,2,3,4,5
  • 1,5,3,2,4
  • 1, 4, 3, 5, 2
  • 2, 18, 27, 43, 96

Answer:

  • sort(x): 2, 18, 27, 43, 96
  • order(x): 1, 5, 3, 2, 4
  • rank(x) : 1, 4, 3, 5, 2
  • none of these :  1, 2, 3, 4, 5

Step-by-step explanation:

Given the vector x: x <- c(2, 43, 27, 96, 18)

<u>Sort</u>

In R, the sort(x)  function is used to arrange the entries in ascending or descending order. By default, R will sort the vector in ascending order.

Therefore, the output that matches the sort function is:

sort(x): 2, 18, 27, 43, 96

<u>Rank</u>

The rank function returns a vector with the "rank" of each value.

x <- c(2, 43, 27, 96, 18)

  • 2 has a rank of 1
  • 43 has a rank of 4
  • 27 has a rank of 3
  • 96 has a rank of 5
  • 18 has a rank of 2

Therefore, the output of rank(x)  is: 1, 4, 3, 5, 2

<u>Order</u>

When the function is sorted, the order function gives the previous location of each of the element of the vector.

Using the sort(x) function, we obtain: 2, 18, 27, 43, 96

In the vector: x <- c(2, 43, 27, 96, 18)

  • 2 was in the 1st position
  • 18 was in the 5th position
  • 27 was in the 3rd position
  • 43 was in the 2nd position
  • 96 was in the 4th position

Therefore, the output of order(x) is: 1, 5, 3, 2, 4

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Mr. Ayer cuts one melon into 8 equal pieces. write the number 1 as a sum unit fractions that name each piece of melon.
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Answer:

<u>Domain</u>: input values (x-values)

<u>Range</u>: output values (y-values)

<u>Increasing function</u>:  the average rate of change is positive

<u>Decreasing function</u>: the average rate of change is negative

<u>Constant function</u>: y-values do not vary, regardless of x-values

<h3><u>Graph 1</u></h3>

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Domain: [-2, 3]

Range:  [-2, 2]

Increasing function: (-2, 0)

Decreasing function:  (0, 3)

<h3><u>Graph 2</u></h3>

From inspection of the graph, 2 squares = 1 unit.

Domain: [-2, 3]

Range: [-2.5, 2]

Increasing function: (-2, -1) ∪ (1.5, 3)

Decreasing function:  (-1, 1.5)

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Range: [-1, 2]

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