Question

What is the value of y? 3/3 units 53 units 9 3 units 12/3 units

Answer 1

Answer:

$y=6\sqrt{3}$

Step-by-step explanation:

Using the Pythagoras theorem for triangle MTU,

$TU^2+3^2=6^2$

$TU^2+9=36$

$TU^2=36-9$

$TU^2=27$

$TU^2=27$

From, triangle NTU,

$y^2=TU^2+NU^2$

This implies that:

$y^2=27+9^2$

$y^2=27+81$

$y^2=108$

$y=\sqrt{108}$

$y=6\sqrt{3}$ units.

Answer 2

Answer:

The value of y=6√3 units.

Step-by-step explanation:

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