Multiply 1st equation by 5
-5x + 10y = -20
now you have
-5x + 10y = -20
5x - 10y = 20
---------------------add
0 + 0 = 0
0 = 0
answer
C. the system has infinitely many solutions
Answer:
I’m pretty sure it’s 6 but I’m not 100% sure
Step-by-step explanation:
346788 ese es la ª
B a 135899933
Hello from MrBillDoesMath!
Answer:
x = 2 and 10
Discussion:
Approach 1:
20 = (-10)*(-2) and (-10) + (-2) = -12 the coefficients of the polynomial. Hence
x^2 -12x + 20 = ( x- 2) * ( x-10)
Approach 2:
From the quadratic formula ( a = 1, b = -12, c = 20)
x = ( -(-12) +\- sqrt( ((-12)^2 - 4*1*20) ) / (2 * 1)
= ( 12 +\- sqrt( 144-80) ) /2
= (12 +\- sqrt(64) ) /2
= (12 +\- 8 ) /2
x = ( 12 + 8) /2 = 20/2 = 10
or
x = ( 12 - 8)/ 2 = 4/2 = 2
Thank you,
MrB