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3 years ago

A line has a slope of 3 and a y-intercept of 4. What is the equation of the line in Slope Intercept Form?

Mathematics

2 answers:

Vedmedyk [2.9K]3 years ago

8 0

The answers are right there for you, all you have to do is plug them in

m=3
y-int.= 4
y=mx+b

y=3x+4

Doss [256]3 years ago

3 0

Answer: y=3x+4

Step-by-step explanation:

Since 3 is slope you add x and since 4 is the y intercept u put it behind an addition sign since it isn’t negative, but if it was negative it would be y=3x-4

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3 years ago

Question regarding logarithms.

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$5^{x-2}-7^{x-3}=7^{x-5}+11\cdot5^{x-4}\\\\5^{x-2}-7^{x-2-1}=7^{x-2-3}+11\cdot5^{x-2-2}\qquad\text{use}\ \dfrac{a^n}{a^m}=a^{n-m}\\\\5^{x-2}-\dfrac{7^{x-2}}{7^1}=\dfrac{7^{x-2}}{7^3}+11\cdot\dfrac{5^{x-2}}{5^2}\\\\5^{x-2}-\dfrac{1}{7}\cdot7^{x-2}=\dfrac{1}{343}\cdot7^{x-2}+\dfrac{11}{25}\cdot5^{x-2}\\\\-\dfrac{1}{7}\cdot7^{x-2}-\dfrac{1}{343}\cdot7^{x-2}=\dfrac{11}{25}\cdot5^{x-2}-5^{x-2}\\\\\left(-\dfrac{1}{7}-\dfrac{1}{343}\right)\cdot7^{x-2}=\left(\dfrac{11}{25}-1\right)\cdot5^{x-2}$

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$\dfrac{5^2\cdot5^2}{7^3\cdot7}=\left(\dfrac{5}{7}\right)^{x-2}\qquad\text{use}\ a^n\cdot a^m=a^{n+m}\\\\\dfrac{5^4}{7^4}=\left(\dfrac{5}{7}\right)^{x-2}\\\\\left(\dfrac{5}{7}\right)^4=\left(\dfrac{5}{7}\right)^{x-2}\iff x-2=4\qquad\text{add 2 to both sides}\\\\\boxed{x=6}$

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3 years ago

Read 2 more answers

I need help on these ??!!

lana [24]

Could i see the rest of the answer?

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2 years ago