Question

The perimeter of a rectangle is 52 cm. If its width is 2 cm more than one-third of its length, find the dimensions of rectangle.

Answer 1

Answer:

(B) 18 cm x 8 cm

Step-by-step explanation:

let the length be x,

then the width is $\frac{1}{3}$x + 2

2( $\frac{1}{3}$x + 2 + x ) = 52

$\frac{1}{3}$x + 2 + x  = 26

$\frac{4}{3} x$ = 24

x = (24*3)/4

x = 18

then the length is 18 cm

and width is (1/3)*18 + 2 = 8

Therefore the dimensions are length:width = 18 cm : 8 cm

Answer 2

Answer:

(B) 18cm x 8cm

Step-by-step explanation:

Perimeter of a rectangle  =  52 cm

2(length + width)  =  52 ==>  l + w  =  26

Let x be the length

width  =  (x/3) + 2

x + (x/3) + 2  =  26

[(3x + x)/3]  + 2 =  26

4x / 3  =  24

4x  =  24 (3)

x  =  6(3) ==>  18 cm

Width  =  (18/3) + 2

=  6 + 2  =  8 cm

So, the required dimension is 18 cm x 8 cm.