Question

a ball is thrown vertically upward from the ground with an initial velocity of 60 ft/sec. how high will the ball go?

Answer 1

Answer:

The ball will go to maximum height of 56.25 meters.

Step-by-step explanation:

It is given that, a ball is thrown vertically upward from the ground. Initial velocity of the ball, v = 60 ft/sec

Initial height is 0 as the ball is thrown from ground. The equation of projectile is given by :

$h(t)=-16t^2+vt+h$

h = 0

$h(t)=-16t^2+60t$..............(1)

We need to find the maximum height reached by the ball. For maximum height,

$\dfrac{dh(t)}{dt}=0$

$\dfrac{d(-16t^2+60t)}{dt}=0$

t = 1.875 seconds

Put the values of t in equation (1). So,

$h(t)=-16(1.875)^2+60(1.875)$

h(t) = 56.25 meters

So, the ball will go to maximum height of 56.25 meters. Hence, this is teh required solution.