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Free_Kalibri [48]
4 years ago
11

Help! 20 points. Show step-by-step solution.

Mathematics
1 answer:
IceJOKER [234]4 years ago
5 0
Use the quadratic formula and plug in the coefficients

3x - 9 {x}^{2} = - 10 \\ - 9 {x}^{2} + 3x + 10 = 0 \\ b = 3 \\ a = - 9 \\ c = 10 \\ - \frac{3 + \sqrt{ {3}^{2} - 4( - 9)(10) } }{2( - 9)} \\ \frac{ - 3 + \sqrt{9 + 360} }{ - 18} \\ \frac{ - 3 + 3 \sqrt{41} }{{ - 18} } \\ \frac{ - 1 + \sqrt{41} }{ - 6}

I wasn't able to the plus or minus sign in so I just used the plus sign you can look up the quadratic formula online
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Step-by-step explanation:

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Simplify completely: the quantity 8 times x to the third power plus 6 times x to the 2nd power minus 4 times x all over negative
True [87]
The answer is <span>a.−4x^2 − 3x + 2
</span>
the quantity 8 times x to the third power plus 6 times x to the 2nd power minus 4 times x all over negative 2 times x is: \frac{8 x^{3}+6 x^{2} -4x }{-2x}

\frac{8 x^{3}+6 x^{2} -4x }{-2x} =  -\frac{8 x^{3}+6 x^{2} -4x }{2x}=- \frac{2x*4 x^{2} +2x*3x-2x*2}{2x} =- \frac{2x(4x^{2} +3x-2)}{2x} = \\  \\ =-(4x^{2} +3x-2)=-4x^{2} -3x+2
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3 years ago
The price of a holiday was decreased by 12 percent to 600 . What was the price before the decrease?
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Price before decrease = x

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