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dybincka [34]
3 years ago
11

5a+9b-4. What is the coefficient

Mathematics
1 answer:
inessss [21]3 years ago
5 0

Answer:

The coefficients in this expression are 5 and 9 because they have a variable in front of them.  

-4 is a constant because it doesn’t have a variable in front of it.  

The terms are 5a, 9b, -4.

Step-by-step explanation:

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A. Use composition to prove whether or not the functions are inverses of each other.
kogti [31]

A. In a composition of two functions the first function is evaluated, and then the second function is evaluated on the result of the first function. In other word, you are going to evaluate the second function in the first function.

Remember that you can evaluate function at any number just replacing the variable in the function with the number. For example, let's evaluate our function f(x) at x=1:

f(x)=\frac{1}{x-3}

f(1)=\frac{1}{1-3}

f(1)=\frac{1}{-2}

Similarly, to find the composition of f(x) andg(x), we are going to evaluate f(x) at g(x). In other words, we are going to replace x in f(x) with \frac{3x+1}{x}:

f(x)=\frac{1}{x-3}

f(g(x) = f(\frac{3x+1}{x} ) = \frac{1}{\frac{3x+1}{x} -3}

Remember that two functions are inverse if after simplifying their composition, we end up with just x. Let's simplify and see what happens.

f(g(x)=\frac{1}{\frac{3x+1}{x} -3}

f(g(x)=\frac{1}{\frac{3x+1-3x}{x} }

f(g(x)=\frac{1}{\frac{1}{x} }

f(g(x)=x

Now let's do the same for g(f(x)):

g(\frac{1}{x-3} )=\frac{3(\frac{1}{x-3})+1}{x}

g(\frac{1}{x-3} )=\frac{\frac{3}{x-3}+1}{x}

g(\frac{1}{x-3} )=\frac{\frac{3+x-3}{x-3}}{x}

g(\frac{1}{x-3} )=\frac{\frac{x}{x-3}}{x}

g(\frac{1}{x-3} )=\frac{x}{x(x-3)}

g(f(x))=\frac{x}{x(x-3)}

We can conclude that g(x) is the inverse function of f(x), but f(x) is not the inverse function of g(x).

B. The domain of a function is the set of all the possible values the independent variable can have. In other words, the domain are all the possible x-values of function.

Now, interval notation is a way to represent and interval using an ordered pair of numbers called the end points; we use brackets [ ] to indicate that the end points are included in the interval and parenthesis ( ) to indicate that they are excluded.

Notice that when x=0, g(x)=\frac{3(0)+1}{0} =\frac{0}{0}, so when x=0, g(x) is not defined; therefore we have to exclude zero from the domain of f(g(x)).

We can conclude that the domain of the composite function f(g(x)) in interval notation is (-∞,0)U(0,∞)

Now let's do the same for g(f(x)).

Notice that the composition is not defined when its denominator equals zero, so we are going to set its denominator equal to zero to find the values we should exclude from its domain:

x(x-3)=0

x=0 and x-3=0

x=0 and x=3

Know we know that we need to exclude x=0 and x=3 from the domain of g(f(x)).

We can conclude that the domain of the composition function g(f(x)) is (-∞,0)U(0,3)U(3,∞)

4 0
3 years ago
Read 2 more answers
What is the imaginary part of the complex number plotted on this graph? 3 -2i -2 3i
borishaifa [10]
The point is at an x value of -2 and it goes up the imaginary axis 3 units, so the imaginary part of the complex number is 3i. 
5 0
3 years ago
Read 2 more answers
Sarina throws a ball up into the air, and it falls on the ground nearby. The ball's height, in feet, is modeled by the function
tangare [24]

Answer:

(C) 3 feet

Step-by-step explanation:

We have a function of f(x) here. When Sarina throws the ball, it has been 0 seconds since she threw it.

Since x represents the amount of seconds, we can find the height of the ball (f(x)) by substituting x in as 0.

-0^2 - 0 + 3

0 squared is 0, 0 minus zero is 0, and 0+3 = 3, so

f(x) = 3

Meaning that when Sarina threw the ball, it's height was 3 feet.

Hope this helped!

7 0
3 years ago
How many times bigger is 6.4*10^9 than 1.3*10^9
sukhopar [10]

Answer:

at least four times bigger

5 0
3 years ago
Per<br> (in meters)<br> 3.23<br> 3.18<br> 3.22<br> 3.19
alisha [4.7K]

Answer:

Can you please be more specific what do I convert it to.

Step-by-step explanation:

3 0
3 years ago
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