How many times bigger is 6.4*10^9 than 1.3*10^9

Illusion [34]

Answer:

20x

Step-by-step explanation:

You would multiply 1/4 times 8. Or instead, you could divide 80 by 4. You would get 20 then you would multiply that by x and get 20x. Hope this helps.

6 0

2 years ago

A bowl has the shape of a hemisphere whose diameter is 14 centimeters. If this bowl is filled with water, how many cubic centime

ASHA 777 [7]

Answer:

The cubic centimeters of water it will take to fill the bowl is 718.67 cm³

Step-by-step explanation:

Given;

diameter of the hemisphere, d = 14 cm

radius of the hemisphere, r = d/2 = 14/2 = 7 cm

The volume of the hemisphere is calculated as;

$V = \frac{2}{3} \pi r^3\\\\V = \frac{2}{3} \times \frac{22}{7} \times (7 \ cm)^3\\\\V = 718.67 \ cm^3$

The cubic centimeters of water it will take to fill the bowl is 718.67 cm³

4 0

3 years ago

Hot dog buns come in packages of 8.For

Nostrana [21]

240 because 8 times 30 equals 240

5 0

3 years ago

Read 2 more answers

Alex invests his money in an account paying 2% interest compounded semiannually. What is the effective annual yield on this acco

Travka [436]

Answer: 2.01%.

Step-by-step explanation:

Suppose Alex invests $1 into the account for one year. The formula is A=P0⋅(1+rk)N⋅k with P0=$1. We know that r=0.02 and k=2 compounding periods per year. Now, N=1 year. Substituting the values we have A=$1⋅(1+0.022)2=$1.0201. Now, to calculate the effective annual yield, we will use the formula rEFF=A−P0P0. rEFF=1.0201−11=0.0201 or 2.01%. When rounded to two decimals, rEFF=2.01%. However, do not include the % in your answer.

3 0

2 years ago

PLEASE HELP!!!!!!!dgbdgdbhdndcn

bogdanovich [222]

Problem 1)

AC is only perpendicular to EF if angle ADE is 90 degrees

(angle ADE) + (angle DAE) + (angle AED) = 180
(angle ADE) + (44) + (48) = 180
(angle ADE) + 92 = 180
(angle ADE) + 92 - 92 = 180 - 92
angle ADE = 88

Since angle ADE is actually 88 degrees, we do NOT have a right angle so we do NOT have a right triangle

Triangle AED is acute (all 3 angles are less than 90 degrees)

So because angle ADE is NOT 90 degrees, this means AC is NOT perpendicular to EF

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Problem 2)

a) The center is (2,-3)

The center is (h,k) and we can see that h = 2 and k = -3. It might help to write (x-2)^2+(y+3)^2 = 9 into (x-2)^2+(y-(-3))^2 = 3^3 then compare it to (x-h)^2 + (y-k)^2 = r^2

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b) The radius is 3 and the diameter is 6

From part a), we have (x-2)^2+(y-(-3))^2 = 3^3 matching (x-h)^2 + (y-k)^2 = r^2

where
h = 2
k = -3
r = 3

so, radius = r = 3
diameter = d = 2*r = 2*3 = 6

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c) The graph is shown in the image attachment. It is a circle with center point C = (2,-3) and radius r = 3.

Some points on the circle are

A = (2, 0)
B = (5, -3)
D = (2, -6)
E = (-1, -3)

Note how the distance from the center C to some point on the circle, say point B, is 3 units. In other words segment BC = 3.

6 0

3 years ago