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2 years ago

15

(4xy+x^2y+4)(xy+y^2)

1 answer:

marysya [2.9K]2 years ago

4 0

If I read this right, the answer should be $x^{2y+4}y^{2}+x^{2y+5}y+4x^{2}y^{2}+4xy^{3}$ .

Hope that helped!!

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Help me with writing this exression please

k0ka [10]

Answer:

3 * n^(1/6)

Step-by-step explanation:

The square root can be written as ^ 1/2

The cube root can be written as ^ 1/3

So the sixth root can be written as ^ 1/6

3 * n^(1/6)

5 0

3 years ago

Determine the quotient, q(x), and remainder, r(x) when

Fed [463]

ANSWER

Quotient:

$q(x) = {x}^{2} - 4x + 7\\$

Remainder:

$r(x) = 11x - 29$

EXPLANATION

The given functions are

$f(x) = 4 {x}^{4} + 12 {x}^{3} + 17 {x}^{2} + 19x + 6$

and

$g(x) = 4 {x}^{2} + 4x + 5$

We want to find the quotient and the remainder when f(x) is divided by g(x).

We perform the long division as shown in the attachment.

The quotient is

$q(x) = {x}^{2} - 4x + 7$

The remainder is

$r(x) = 11x - 29$

5 0

3 years ago

How much interest would be earned on a $3,200 deposit at 3.5% for 1 year?

Fynjy0 [20]

Answer:

Hey there!

I=PRT

I=3200(0.035)(1)

I=112

The interest is 112 dollars.

Hope this helps :)

5 0

3 years ago

Read 2 more answers

Help me please i am confused on what to do

padilas [110]

It would be 32 minutes

5 0

3 years ago

Read 2 more answers

A triangle has a base of x 1/2 m and a height of x 3/4 m. If the area of te triangle is 16m to the power of 2, what are the base

Olenka [21]

Answer:

The base of triangle is $\frac{8}{\sqrt{3}} \ m$ and the height of triangle is $\frac{12}{\sqrt{3}} \ m.$

Step-by-step explanation:

Given:

A triangle has a base of x 1/2 m and a height of x 3/4 m. If the area of the triangle is 16m to the power of 2.

Now, to find the base and height of the triangle.

The base of triangle = $x\times\frac{1}{2} =\frac{x}{2} \ m.$

The height of triangle = $x\times \frac{3}{4} =\frac{3x}{4}\ m.$

The area of triangle = $16\ m^2.$

Now, we put the formula of area to solve:

$Area=\frac{1}{2} \times base\times height$

$16=\frac{1}{2} \times \frac{x}{2} \times \frac{3x}{4}$

$16=\frac{3x^2}{16}$

<em>Multiplying both sides by 16 we get:</em>

<em /> $256=3x^2$ <em />

<em>Dividing both sides by 3 we get:</em>

<em /> $\frac{256}{3} =x^2$ <em />

<em>Using square root on both sides we get:</em>

$\frac{16}{\sqrt{3}}=x$

$x=\frac{16}{\sqrt{3}}$

Now, by substituting the value of $x$ to get the base and height:

$Base=\frac{x}{2}\\\\Base=\frac{\frac{16}{\sqrt{3}}}{2} \\\\Base=\frac{8}{\sqrt{3}} \ m.$

<em>So, the base of triangle = </em> $\frac{8}{\sqrt{3}} \ m.$ <em />

$Height=x\times\frac{3}{4} \\\\Height=\frac{16}{\sqrt{3}}\times \frac{3}{4} \\\\Height=\frac{12}{\sqrt{3}} \ m.$

<em>Thus, the height of triangle = </em> $\frac{12}{\sqrt{3}} \ m.$ <em />

Therefore, the base of triangle is $\frac{8}{\sqrt{3}} \ m$ and the height of triangle is $\frac{12}{\sqrt{3}} \ m.$

7 0

3 years ago