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3 years ago

What is the maximum number of solutions each of the following systems could have?

Mathematics

2 answers:

lapo4ka [179]3 years ago

8 0

Answer:

0,2,2,4

Step-by-step explanation:

lesantik [10]3 years ago

6 0

Answer:

Two distinct concentric circles: 0 max solutions

Two distinct parabolas: 4 max solutions

A line and a circle: 2 max solution

A parabola and a circle: 4 max solutions

Step-by-step explanation:

Two distinct concentric circles:

The maximum number of solutions (intersections points) 2 distinct circles can have is 0. You can see an example of it in the first picture attached. The two circles are shown side to side for clarity, but when they will be concentric, they will have same center and they will be superimposed. So there can be ZERO max solutions for that.

Two distinct parabolas:

The maximum solutions (intersection points) 2 distinct parabolas can have is 4. This is shown in the second picture attached. This occurs when two parabolas and in perpendicular orientation to each other.

A line and a circle:

The maximum solutions (intersection points) a line and a circle can have is 2. See an example in the third picture attached.

A parabola and a circle:

The maximum solutions (intersection points) a parabola and a circle can have is 4. If the parabola is compressed enough than the diameter of the circle, there can be max 4 intersection points. See the fourth picture attached as an example.

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The company in the example on page 301 decides to increase the capacity of its large bottles from 32 fl oz to 40 fl oz. It plans

Leviafan [203]

Answer:

Cost of new bottle = 1.25a

Step-by-step explanation:

Given:

Volume of old bottle = 32 fl oz

Volume of new bottle = 40 fl oz

Computation:

Assume price ratio of old bottle = a

So,

Price ratio of new bottle [Compare by capacity] = [40/32]a

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8 0

3 years ago

Definition of corresponding angles

Serggg [28]

Answer:

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3 years ago

A baker uses 13 1/2 cups of flour to make bread. She uses 2 1/4 cups of flour to make each loaf. The baker sells 2/3 of the loav

ollegr [7]

Answer:

She sells 4 loaves of bread

Step-by-step explanation:

Lets explain how to solve the problem

→ A baker uses $13\frac{1}{2}$ cups of flour to make bread

→ She uses $2\frac{1}{4}$ cups of flour to make each loaf

From these information we can find the number of loaves of bread

she can make

∵ There are $13\frac{1}{2}$ cups of flour

∵ Each loaf of bread needs $2\frac{1}{4}$ cups of flour

∴ The number of loaves = $13\frac{1}{2}$ ÷ $2\frac{1}{4}$

To divide two mixed numbers make them improper fractions and

change the division sign to multiplication sign and reciprocal the

fraction after the division sign

∵ $13\frac{1}{2}$ = $\frac{(13)(2)+1}{2}$

∴ $13\frac{1}{2}$ = $\frac{27}{2}$

∵ $2\frac{1}{4}$ = $\frac{(2)(4)+1}{4}$

∴ $2\frac{1}{4}$ = $\frac{9}{4}$

∴ The number of loaves = $\frac{27}{2}$ × $\frac{4}{9}$

∴ The number of loaves = 6

She can make 6 loaves

→ The baker sells $\frac{2}{3}$ of the loaves of bread that she makes

→ We need to find the number of loves of bread she sells

∵ She sells $\frac{2}{3}$ of the loaves

∵ There are 6 loves

∴ The number of loaves she sells = 6 × $\frac{2}{3}$ = 4

She sells 4 loaves of bread

7 0

3 years ago

Helppp!!!! please!!!

postnew [5]

Answer:

256m^2.

Step by step:

Well now let’s find the area of a square which is 8*8 = 64.
And now let’s find the area of a triangle using the formula 12*8 / 2 = 48.
And since there is 4 sides we multiply 48 by 4 which is 192.
so 192 + 64 is 256m^2.

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KATRIN_1 [288]

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