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Answer:
<em>$50,000 was borrowed at 9%.</em>
<em>$125,000 was borrowed at 10%.</em>
<em>$75,000 was borrowed at 12%.</em>
Step-by-step explanation:
Let amount borrowed at 9% be x
Let amount borrowed at 10% be y
Let amount borrowed at 12% be z
Now equations form:
....(1)
....(2)
..... (3)
Substituting the value of y from (3) in (1) and (2)
=> ......(4)
=> ....(5)
Multiplying (4) by 0.12 and subtracting (5) from it, we get
-
0.08x=4000
x = $50000
As y = 2.5x
So,
y = $125000
And as x+y+z=250000
=>
z = $75000
Therefore, <em>$50,000 was borrowed at 9%.</em>
<em>$125,000 was borrowed at 10%.</em>
<em>$75,000 was borrowed at 12%.</em>