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Andreas93 [3]
3 years ago
5

What is the slope of the line

Mathematics
1 answer:
Oliga [24]3 years ago
3 0

Answer:

The slope is 1

Step-by-step explanation:

Lets pick two points on the line

(0,1)   and (-1,0)

  We can use the slope equation

m = (y2-y1)/(x2-x1)

   = (0-1)/(-1 -0)

   =-1/-1

   =1

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vovikov84 [41]
The first one is true
5 0
3 years ago
The concentration of particles in a suspension is 50 per mL. A 5 mL volume of the suspension is withdrawn. a. What is the probab
kolezko [41]

Answer:

(a) 0.6579

(b) 0.2961

(c) 0.3108

(d) 240

Step-by-step explanation:

The random variable <em>X</em> can be defined as the number of particles in a suspension.

The concentration of particles in a suspension is 50 per ml.

Then in 5 mL volume of the suspension the number of particles will be,

5 × 50 = 250.

The random variable <em>X</em> thus follows a Poisson distribution with parameter, <em>λ</em> = 250.

The Poisson distribution with parameter λ, can be approximated by the Normal distribution, when λ is large say λ > 10.  

The mean of the approximated distribution of X is:

μ = λ  = 250

The standard deviation of the approximated distribution of X is:

σ = √λ  = √250 = 15.8114

Thus, X\sim N(250, 250)

(a)

Compute the probability that the number of particles withdrawn will be between 235 and 265 as follows:

P(235

                             =P(-0.95

Thus, the value of P (235 < <em>X</em> < 265) = 0.6579.

(b)

Compute the probability that the average number of particles per mL in the withdrawn sample is between 48 and 52 as follows:

P(48

                             =P(-0.28

Thus, the value of P(48.

(c)

A 10 mL sample is withdrawn.

Compute the probability that the average number of particles per mL in the withdrawn sample is between 48 and 52 as follows:

P(48

                             =P(-0.40

Thus, the value of P(48.

(d)

Let the sample size be <em>n</em>.

P(48

                             0.95=P(-z

The value of <em>z</em> for this probability is,

<em>z</em> = 1.96

Compute the value of <em>n</em> as follows:

z=\frac{\bar X-\mu}{\sigma/\sqrt{n}}\\\\1.96=\frac{48-50}{15.8114/\sqrt{n}}\\\\n=[\frac{1.96\times 15.8114}{48-50}]^{2}\\\\n=240.1004\\\\n\approx 241

Thus, the sample selected must be of size 240.

5 0
3 years ago
How to solve z+2/z-3=5/-3
OLEGan [10]
(z+2)= (z-3)(5/-3)
z+2 = 5z/-3 +5
-3= 2z/-3
9= 2z
9/2 = z
5 0
3 years ago
Solve this inequality j/4 - 8 &lt; 4
zubka84 [21]
J/4 - 8 < 4
<u>    + 8   + 8  </u>   *add 8 to both sides to cancel -8.
j/4      < 12
<u>*4/1       *4/1   </u>   *multiply 4/1 to both sides to cancel 1/4
j         < 48

j should be less than 48 to make the inequality true.

example: j = 47
j/4       - 8 < 4
47/4   - 8 < 4
11.75 - 8 < 4
       3.75 < 4  

Any number below 48 will end up with an answer less than 4. if j is 48 and above, the inequality is false because the answer arrived at will be equal to or greater than 4.
5 0
3 years ago
Is 9/15 irrational??
Mariana [72]

No because irrational cant be a simple fraction and 9/15

is 0.6

so... it is not irrational

4 0
3 years ago
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