If sales increase by $1500 in a week , do you think profit for the will also increase by about $1500?"

Mathematics

1 answer:

kari74 [83]4 years ago

8 0

In general, Profit is the difference of Total Sales and Total Expences.

In formula form we could write it,

Profit = Total Sales - Total Expences.

According to given problem, sales increase by $1500 in a week.

That is some more sales also added to previous sales but still some expences are included in total sales and even in increased sale $1500.

So, in order to get the net profit, we need to subtract all expences (even the original cost in making the product and expences of all servises provided in sales).

Therefore, we could finally say, "if sales increase by $1500 in a week, profit would not increase by about $1500".

You might be interested in

Find the surface area of this net.

Elden [556K]

Answer:

Step-by-step explanation:

First, let's find the surface area of both the triangles

5x3=15

So, the surface area of the triangles is 15 sq.cm

Now, let's find the surface area of the base (large rectangle in the middle)

12x8=?

10x8=80

2x8=16

80+16=96

12x8=96

So, the surface area of the base, is 96sq.cm

Now, let's find the surface area of both of the side rectangles

12x5=60

60x2=120

So, the surface area of the two side rectangles is 120sq.cm

Now, let's find the total surface area by adding all of our answers.

120+96=216

216+15=231

<h2>So hence, the surface area of this net is 231cm²</h2>

3 0

2 years ago

SHALL GIVE BRAINLIEST ANSWER!! A 40% solution of fertilizer is to be mixed with an 80% solution of fertilizer in order to get

sdas [7]

Answer:

20 gallons of the 40% solution, 60 gallons of the 80% solution

Step-by-step explanation:

Let x = the gallons of the 40% solution, and y = the gallons of a 80% solution. The first thing we want to do here is to convert each percentage into decimal form - including the 70% solution mixture.

40% = 0.40,

80% = 0.80, respectively 70% = 0.70

As you can tell, 0.40 is associated with x gallons, 0.80 is associated with y gallons, and the mixture contains 0.70 $*$ 80 solution, as 0.70 is associated with 80. Therefore we can formulate the following expression,

0.40x + 0.80y = 0.70 $*$ 80

At the same time x + y = 80, as the solution ( mixture ) is present with 80 gallons. Isolating x, x = 80 - y. Let us plug that into our expression, solving for y, following by x gallons.

$0.40\left(\:80\:-\:y\:\right)\:+\:0.80y\:=\:0.70\:\cdot \:80$