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bonufazy [111]
3 years ago
10

Pls hel fast simplify 10^0

Mathematics
2 answers:
polet [3.4K]3 years ago
8 0

Answer:

1/0

Step-by-step explanation:

hope we can be friends

can i please get brainliest

Softa [21]3 years ago
7 0

Answer:

1

Step-by-step explanation:

any number to the power of 0 is one

Hope this helps :)

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Please answer this question above.
ioda
The distance between point J and line KL would be the line perpendicular to the line, which is line JM.

The answer would be B.
7 0
3 years ago
The line defined by the equation 2y+3=-(2/3)(x-3) is tangent to the graph of g(x) at x=-3. What is the value of the limit as x a
Otrada [13]
<span>the limit as x approaches -3 of [g(x)-g(-3)]over(x+3) is the same as the derivative, or slope, of g(x) at the point x=-3, or g'(-3).
Since you are given the equation of the tangent line, the answer is just the slope of that line.
</span><span>2y+3=-(2/3)(x-3)
</span><span>6y+9=-2(x-3)
6y+9=-2x+6
6y=-2x-3
y= (-2x-3)/6
slope is -2/6 = </span>\boxed{ -\frac{1}{3} }
8 0
3 years ago
WILL GIVE BRAINLY Find the perimeter of the figure below, in meters.
yan [13]

Answer:

147.6\:\mathrm

Step-by-step explanation:

The perimeter of a polygon is simply sum of the lengths of all sides of the polygon.

Therefore, we can find this polygon's perimeter by adding up the length of each of its sides:

9.8+9.8+11.7+9.8+21.5+21+11.7+9.8+31.3+11.2=\boxed{147.6\:\mathrm{m}}

Since there is a lot to keep track of, I'd recommend picking any side and moving clockwise/counter-clockwise until you get all sides.

3 0
3 years ago
A cubical reservoir has capacity of 480000 l itters of liquid. If ifs length and breadth are 10m and 8m respectively, find the h
sertanlavr [38]

Answer:

Height = 6000 m

Step-by-step explanation:

Volume = length \times breadth \times height \\\\480000 = 10 \times 8 \times  height\\\\480000 = 80 \times height\\\\height = \frac{480000}{80} =  6000 \ m

5 0
3 years ago
How many rational numbers are between 1 and 6?
gregori [183]

one ans six are infinite

6 0
3 years ago
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