The distance between point J and line KL would be the line perpendicular to the line, which is line JM.
The answer would be B.
<span>the limit as x approaches -3 of [g(x)-g(-3)]over(x+3) is the same as the derivative, or slope, of g(x) at the point x=-3, or g'(-3).
Since you are given the equation of the tangent line, the answer is just the slope of that line.
</span><span>2y+3=-(2/3)(x-3)
</span><span>6y+9=-2(x-3)
6y+9=-2x+6
6y=-2x-3
y= (-2x-3)/6
slope is -2/6 = </span>
Answer:

Step-by-step explanation:
The perimeter of a polygon is simply sum of the lengths of all sides of the polygon.
Therefore, we can find this polygon's perimeter by adding up the length of each of its sides:

Since there is a lot to keep track of, I'd recommend picking any side and moving clockwise/counter-clockwise until you get all sides.