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Papessa [141]
3 years ago
7

What is a word phrase for 7C - 3

Mathematics
1 answer:
kogti [31]3 years ago
8 0
7 multiplicated to c minus 3.
You might be interested in
Simplify 3/8 and 9/64<br><br> PLEASE HELP
Andrew [12]

Answer:

3/8 simplified is still 3/8 (0.375 in decimal form)

9/64 simplified is also still 9/64 (0.140625 in decimal form)

Step-by-step explanation:

5 0
3 years ago
A right angled triangle has two shorter sides and one is twice as long as the other. The hypotenuse is 25cm long. What are the l
Bas_tet [7]

Answer:  x =  14.43

Step-by-step explanation:

The Pythagorean Theorem states the following:  

a^2 + b^2 = c^2  

Make one side of the triangle x  

Make the second side of the triangle 2x  

Now, you can plug the values into the equation,  right?  

x^2 + 2x^2 = 25^2 or 625  

3x^2 = 625

Divide each side by 3 and you are left with:  

x^2 =  208.33

Now, take the square root of 208.33

x =  14.43

That is the shorter side. The longer side is twice that value: Therefore, 14.43 x 2 = 28.86 14.43 is one side of the triangle. The other is that same value times two. Therefore, the sides of your triangle are: 14.43 Shorter side 28.86 Longer side

5 0
4 years ago
Read 2 more answers
5y+4x=10.51 8y+3x=10.39
Phoenix [80]

Answer:

  (x, y) = (1.89, 0.59)

Step-by-step explanation:

Written in general form, the equations are ...

  4x +5y -10.51 = 0

  3x +8y -10.39 = 0

These can be solved using the cross-multiplication method to find ...

  ∆1 = (4)(8) -(3)(5) = 17

  ∆2 = (5)(-10.39) -(8)(-10.51) = 32.13

  ∆3 = (-10.51)(3) -(-10.39)(4) = 10.03

Then the values of the variables are ...

  x = ∆2/∆1 = 32.13/17 = 1.89

  y = ∆3/∆1 = 10.03/17 = 0.59

The solution is (x, y) = (1.89, 0.59).

7 0
3 years ago
Help me please thank you
Paladinen [302]
The answer is B, or 2x + 3y - 5 = 0. This is because when you substitute both points in for x and y, you get the values of 0=0, which is true!

5 0
3 years ago
LoJao(37-3八):log 20 (3rniay)
Amanda [17]
Hello,
if the question is to solve the equation:

1) log must exist:
a)==>2r²-27>0==>(r-√(27/2))(r+√(27/2))==> outside the roots
r<-√(27/2) or r>√(27/2)
b)==>3r²+12r>0 ==>3r(r+4)>0 ==>outside the roots
r>0 or r<-4
==>r<-4 or r>√(27/2)=3.6742...

If this is realized:
2r-27=3r²+12r
==>r²+12r+27=0
Δ=12²-4*27=36=6²
r=(-12+6)/2=-3 or r=(-12-6)/2=-9

One solution r=-9

Proof
 log_{20}(2*(-9)^2-27)= log_{20}135

 log_{20}(3*(-9)^2+12*(-9))= log_{20}135



7 0
4 years ago
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