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KonstantinChe [14]
3 years ago
6

What is 1/3 * -1 - 4 ?

Mathematics
2 answers:
disa [49]3 years ago
7 0

Answer:

-14/3 or -4.6

Step-by-step explanation:

I used my calculator and did 1/3 -1 -4

Feliz [49]3 years ago
5 0

Answer:

Step-by-step explanation:

Did you mean (1/3)*(-1-4)?

If yes:

(1/3)*-5=

-5/3

or -1 2/3

Or did you mean ((1/3)*-1) -4?

If so:

(-1/3)-4

-4 1/3

or -13/3

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3 years ago
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Please help, the question below
Licemer1 [7]

Answer:

\sf R=\left(3, -\dfrac{5}{4}\right)

Step-by-step explanation:

Given:

  • P = (1, 5)
  • Q = (-2, 3)
  • R = (a, b)
  • R lies on line x = 3
  • PR = QR

If point R lies on the line x = 3, then the x-value of point R is 3.

⇒ a = 3

<u />

<u>Distance between two points</u>

\sf d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

(where (x₁, y₁) and (x₂, y₂) are the two points)

Use the <u>distance formula</u> to derive equations for PR and QR.

Let (x₁, y₁) = P = (1, 5)

Let (x₂, y₂) = R = (3, b)

\begin{aligned} \sf PR & =\sf \sqrt{(3-1)^2+(b-5)^2}\\ & = \sf \sqrt{4+(b-5)^2} \end{aligned}

Let (x₁, y₁) = Q = (-2, 3)

Let (x₂, y₂) = R = (3, b)

\begin{aligned} \sf QR & =\sf \sqrt{(3-(-2))^2+(b-3)^2}\\ & = \sf \sqrt{25+(b-3)^2} \end{aligned}

As PR = QR, equate the derived equations and solve for b:

\begin{aligned} \sf PR & = \sf QR \\\sf \sqrt{4+(b-5)^2} & = \sf \sqrt{25+(b-3)^2}\\\sf 4+(b-5)^2 & = \sf 25+(b-3)^2\\\sf 4+b^2-10b+25 & = \sf 25 + b^2-6b+9\\\sf b^2-10b+29 & = \sf b^2 -6b +34\\\sf -10b+29 & = \sf -6b + 34\\\sf -4b & = \sf 5\\\sf b & = -\dfrac{5}{4}\end{aligned}

Substitute the found values of a and b to find the coordinates of R:

\sf R=(a,b)=\left(3, -\dfrac{5}{4}\right)

Learn more about the distance formula here:

brainly.com/question/28144723

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