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3 years ago

What is the next term of the arithmetic sequence? -8, -14, -20.–26,

Mathematics

2 answers:

VARVARA [1.3K]3 years ago

6 0

Answer:

-32

Step-by-step explanation:

Subtract 6 to get next term.

raketka [301]3 years ago

6 0

Answer:

-32

Step-by-step explanation:

I'm saying this is the answer because if you look at the pattern of numbers, it keeps decreasing by 6. If you continue this sequence, you will find that you will just have to follow the same pattern of decreasing by 6. This will lead you to get -32 as your next number in your arithmetic sequence.

(Hope this helped you)

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Find |−68|. plz i will give brainlist

Anni [7]

Answer:

Step-by-step explanation:

The lines on both sides of the number represent absolute value. Absolute value takes any number and turns it positive no matter what.

|-68| → 68

Best of Luck!

8 0

3 years ago

A=4,B=7,C=11,D=13. Given the number line, AB=

Oksi-84 [34.3K]

Step-by-step explanation:

AB=28 !... .......hope this helps..

5 0

3 years ago

Read 2 more answers

If the sum of the even integers between 1 and k, inclusive, is equal to 2k, what is the value of k?

Alisiya [41]

If $k$ is odd, then

$\displaystyle\sum_{n=1}^{\lfloor k/2\rfloor}2n=2\dfrac{\left\lfloor\frac k2\right\rfloor\left(\left\lfloor\frac k2\right\rfloor+1\right)}2=\left\lfloor\dfrac k2\right\rfloor^2+\left\lfloor\dfrac k2\right\rfloor$

while if $k$ is even, then the sum would be

$\displaystyle\sum_{n=1}^{k/2}2n=2\dfrac{\frac k2\left(\frac k2+1\right)}2=\dfrac{k^2+2k}4$

The latter case is easier to solve:

$\dfrac{k^2+2k}4=2k\implies k^2-6k=k(k-6)=0$

which means $k=6$ .

In the odd case, instead of considering the above equation we can consider the partial sums. If $k$ is odd, then the sum of the even integers between 1 and $k$ would be

$S=2+4+6+\cdots+(k-5)+(k-3)+(k-1)$

Now consider the partial sum up to the second-to-last term,

$S^*=2+4+6+\cdots+(k-5)+(k-3)$

Subtracting this from the previous partial sum, we have

$S-S^*=k-1$

We're given that the sums must add to $2k$ , which means

$S=2k$
$S^*=2(k-2)$

But taking the differences now yields

$S-S^*=2k-2(k-2)=4$

and there is only one $k$ for which $k-1=4$ ; namely, $k=5$ . However, the sum of the even integers between 1 and 5 is $2+4=6$ , whereas $2k=10\neq6$ . So there are no solutions to this over the odd integers.

5 0

3 years ago

Okay my math final is tomorrow and i need help with variable expressions. If anyone has any websites or apps they recommend, ple

Solnce55 [7]

https://www.google.com/url?sa=t&source=web&rct=j&url=https://www.khanacademy.org/math/algebra/one-variable-linear-equations/alg1-intro-equations/v/variables-expressions-and-equations&ved=2ahUKEwjrpqD1gZziAhUBsp4KHVePBeEQwqsBMAB6BAgHEAU&usg=AOvVaw0AYOWzWFGI7vP8YUOvBhPc Here is a video that's helpful to me

7 0

3 years ago

Is the relationship shown by the data linear? If so, model the data with an equation. X:1,5,9,13 Y:5,10,15,20

ryzh [129]

Let
A (x1,y1)-------> (1,5)
B (x2,y2)------> (5,10)
C (x3,y3)------> (9,15)
D (x4,y4)------> (13,20)

find the slope
AB
m=(10-5)/(5-1)-----> m=5/4

find the slope
CB
m=(15-10)/(9-5)-----> m=5/4

find the slope
DC
m=(20-15)/(13-9)-----> m=5/4

so
<span>the relationship shown is linear
</span>
<span>to model the data with an equation find the equation of a line
</span>with m=5/4 and point A (1,5)
y-y1=m*(x-x1)-----> y-5=(5/4)*(x-1)----> y=1.25x-1.25+5-----> y=1.25x+3.75

the equation to model data is
y=1.25x+3.75

see the attached figure

3 0

3 years ago