Idk what the answer is, sorry
 
        
                    
             
        
        
        
Answer:
D. symbols máy be personal as well as universal
 
        
             
        
        
        
To be non-biased, have thorough research habits, a good work ethic, to produce the story as closely to the true events as possible (no filler or otherwise distracting language to take attention away from the topic)
        
             
        
        
        
The impedance of transformer coil that has 600 feet is 10+j 22.62 Ω (ohms)
Explanation:
It is given that
a #22 copper wire has resistance= R= 10 Ω
                                        inductance= I=0.06 H
                                                              N=60 HZ
X= 2π * N * I
=2 * 3.14 * 60 *0.06
X=22.62 Ω
Impedance is calculated by 
Z = R + j * X
=10+ j (22.62 Ω)
Z= 10+ j 22.62 Ω
The impedance of a transformer coil that has 600 feet is  Z= 10+ j 22.62 Ω