The triangle is not a right triangle. This is because the sum of the square of the two shorter lengths is not equal to the square of the longest length.
<h3>Is the triangle a right triangle?</h3>
In order to determine if the triangle is a right triangle, Pythagoras theorem would be used.
The Pythagoras theorem: a² + b² = c²
where a = length
b = base
c = hypotenuse
12 ² + 24²
= 144 + 576 = 720
29² = 841
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Answer:
The first number (x) = 8
Step-by-step explanation:
Let x = the first number
Let y = the second number
x = 3*y - 4
2x + 3 - 2y = 11 Subtract 3 from both sides
2x - 2y = 11 - 3
2x - 2y = 8 Divide by 2
x - y = 4 Add y to both sides
x = y + 4 Now go back to the very first equation. Substitute for x
y + 4 = 3y - 4 Subtract y from both sides
4 = 3y - y - 4
4 = 2y - 4 Add 4 to both sides
4 + 4 = 2y
8 = 2y Divide by 2
8/2 = y
y = 4
x = 3y - 4
x = 3*4 - 4
x = 12 - 4
x = 8
The largest square that can fit in a square of radius 3cm can have its diagonal length twice its radius.
But diagonal of a square is root square root of {2} x length of each side.
Hence from above, diagonal length is 6 cm and so, the side can be 3*(2^1/2)
So area of square is (3*(2^1/2))^2 = 18 cm^2
Answer:
Im answering in a sec
First is 0
X 4 Y 0
second is 2
X 6 Y 2
Third is 4
X 8 Y 4
PLS mark brainiest if correct
Step-by-step explanation:
Steps of construction:
1. Draw a circle with centre B.
2. Draw a circle with centre C.
3. Both circles intersect each other at a point D
4. Join A and D.
5. So, AD bisects angle CAB.
<em>A </em><em>rough </em><em>figure </em><em>is </em><em>shown</em><em> </em><em>in </em><em>the </em><em>picture</em><em>.</em>