60 student because there are 12 student each group, so 60 student will make 5 group.

Two Angles and the side between them are equal to corresponding Angles and side of another triangle ( one of the Angles are equal because of vertical opposite angle pair ), so the required congruency criteria to prove them equal is :
Answer: The common denomination is 12
Step-by-step explanation:
Answer:
The point C is 12.68 km away from the point A on a bearing of S23.23°W.
Step-by-step explanation:
Given that AB is 50 km and BC is 40 km as shown in the figure.
From the figure, the length of x-component of AC = |AB sin 80° - BC cos 20°|
=|50 sin 80° - 40 cos 20°|=11.65 km
The length of y-component of AC = |AB cos 80° - BC sin 20°|
=|50 cos 80° - 40 sin 20°|= 5 km
tan
= 5/11.65
=23.23°
AC=
km
Hence, the point C is 12.68 km away from the point A on a bearing of S23.23°W.
Answer:
9.62 x 10⁻⁵
Step-by-step explanation:
57 / 592346 = 0.0000962275
Scientific notation: We moved the decimal 5 times to the right, and in order to put the number back in standard form, we have to move the decimal 5 times to the left. So the scientific way of saying this is 9.62 x 10⁻⁵