Answer:
Suppose that A is the set of sophomores at your school and B is the set of students in discrete mathematics at your school.
a) It is the intersection A ∩ B
b) This is the difference A − B.
c) It is the union A ∪ B.
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d) It can be shown as A ∪ B. (bar over A and B both)
Answer:
a) The interval for those who want to go out earlier is between 43.008 and 46.592
b) The interval for those who want to go out later is between 47.9232 and 51.9168
Step-by-step explanation:
Given that:
Sample size (n) =128,
Margin of error (e) = ±4% =
a) The probability of those who wanted to get out earlier (p) = 35% = 0.35
The mean of the distribution (μ) = np = 128 * 0.35 = 44.8
The margin of error = ± 4% of 448 = 0.04 × 44.8 = ± 1.792
The interval = μ ± e = 44.8 ± 1.792 = (43.008, 46.592)
b) The probability of those who wanted to start school get out later (p) = 39% = 0.39
The mean of the distribution (μ) = np = 128 * 0.39 = 49.92
The margin of error = ± 4% of 448 = 0.04 × 49.92 = ± 1.9968
The interval = μ ± e = 44.8 ± 1.792 = (47.9232, 51.9168)
The way for those who want to go out earlier to win if the vote is counted is if those who do not have any opinion vote that they want to go earlier
Answer:
Step-by-step explanation:
In order to find the answer, let's work backwards to find the original. We have to do the opposite to get to the Raju's age. We will start with his fathers age. (44) Then we will subtract five from it so that it will be divisible by three.
44 - 5 = 39
Then we just have to divide by 3.
44/3 = 13
His age is 13 years old.
Answer:
The sports facility is 2,960,000 sq. m in area.
Step-by-step explanation:
The dimension of the sport facility = 0.74 km by 4 km
The Length of the facility = 4 km
The width of the facility = 0.74 km
Now, 1 km = 1000 meters
⇒ 4 km = 4 x (1000) = 4000 meters
and 0.74 km = 0.74 x (1000) = 740 meters
Now, AREA OF THE RECTANGLE = LENGTH x WIDTH
So, the area of the facility = 4000 m x 740 km
= 2,960,000 sq. m
Hence, the sports facility is 2,960,000 sq. m in area.
Answer:
268.08
Step-by-step explanation:
first you take your radius and put it in the equation V=4/3πr³ when you insert the 4 you calculate it to get 268.08257
