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Alisiya [41]
3 years ago
14

Describe the error Sadie made, and explain how to find the correct answer.

Mathematics
2 answers:
ZanzabumX [31]3 years ago
5 0

Answer:

The answer to your question is below

Step-by-step explanation:

Sadie should have left inside the root an exponent lower than the root and the power of "a" is higher than "2", the root is squared.

Right solution

\sqrt{54a^{7}b^{3}  }

54 = 3² 6

a⁷ = a⁶ a

b³ = b² b

                 = \sqrt{3^{2}6 a^{6} a b^{2} b }

                = 3a^{6/2} b^{2/2} \sqrt{6ab}

               = 3 a^{3} b \sqrt{6ab}

amid [387]3 years ago
4 0

Answer:

Sadie did not factor a to the 7th power using the largest perfect power.

Instead of a squared times a to the 5th power, the factors should be a to the 6th times a to the 1st power.

In Sadie’s final answer, the exponent on a should have been 2.

Step-by-step explanation:

Took the test on Edge

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