This is simply a protective mechanism of the body. A person with blood group A will produced antibodies against blood group B because group B cells are considered foreign bodies to the person and will not be tolerated and vice versa. Group B people have antibodies against group A and will not tolerate group A cells. This is why group A person can only be transfused with group A blood or group O blood. Both A and B have no antibodies against blood group O. Indeed no blood group has antibodies against Blood group and this is why people with blood group O are called universal donors.
Group AB people do not have antibodies against any blood group because both these groups are part and parcel of their body and production of antibodies against either A or B would end up in self destruction of the body. Group AB people are known as universal recipients because they can receive blood from any of the other groups.
It is C) Amylase is a catalyst that speeds up the chemical process of breaking down food molecules.
This variation is an example of disruptive selection. The other choices given in the question are incorrect and can be easily neglected. The correct option among all the options that are given in the question is the fourth option or the last option. I hope that this is the answer that has come to your desired help.
D. Both A and B is the correct answer
Answer:
1) The alleles for homozygous brown hair will be BB.
2) The alleles for heterozygous brown hair will be Bb
3) Let's make a punnet square to check for the outcomes:
B b
B BB Bb
B BB Bb
4) The results from the punnet square depict that the phenotype of all the children produced will be brown hair.
5) The punnet square depicts that there will be a 50% probability of the child to carry the heterozygous genome (Bb) and there is also 50% probability for the child to carry homozygous dominant genome (BB).