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alexandr1967 [171]
3 years ago
9

29 to 33 pls it worth 10 points pls do it

Mathematics
1 answer:
Irina18 [472]3 years ago
3 0

32.the answer is 2c+0

this is all I can do for now

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PLEASE ANSWER ASAP the quiz is almost over and I need to turn this in
andriy [413]

Answer:

X = 10

Step-by-step explanation:

the triangles are similar meaning one is smaller we have all the sides on the smaller one

10 to 25 is a 2.5 increase

so 4 x 2.5 = 10

5 0
3 years ago
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Two​ high-speed ferries leave at the same time from a city to go to the same island. The first​ ferry, the​ Cat, travels at 34 m
djyliett [7]

Answer:

They will be 5 miles apart in 1 hour

Step-by-step explanation:

Here, we want to calculate the time it will take for the two ferries to be 5 miles apart

Mathematically; distance = speed * time

Let the number of hours be x

In x hours, the cat will have traveled 34 * x = 34x miles

In x hours, the Bird will have traveled 29 * x = 29x miles

So;

34x - 29x = 5

5x = 5

x = 5/5

x = 1 hour

4 0
3 years ago
RSTU is a parallelogram. If m∠SRV = 48° and m∠SVR = 54°, explain how you can find the measure of ∠TUV. Show all steps of your wo
const2013 [10]

Opposite angles in a parallelogram have equal measure.

The measure of angle TUV is 78 degrees

The given parameters are:

\mathbf{\angle SRV = 48}

\mathbf{\angle SVR = 54}

Start by calculating angle RSV.

\mathbf{\angle RSV + \angle SVR + \angle SRV = 180} --- angles in a triangle

So, we have:

\mathbf{\angle RSV + 54 + 48= 180}

\mathbf{\angle RSV + 102= 180}

Subtract 102 from both sides

\mathbf{\angle RSV = 78}

Angles RSV and TUV are corresponding angles.

So, we have:

\mathbf{\angle TUV = \angle RSV = 78}

Rewrite as:

\mathbf{\angle TUV = 78}

Hence, the measure of angle TUV is 78 degrees

Read more about parallelograms at:

brainly.com/question/12186483

4 0
3 years ago
Read 2 more answers
How to get the answers?​
beks73 [17]

By inclusion/exclusion,

n(P' \cup Q) = n(P') + n(Q) - n(P' \cap Q)

We have

n(\xi) = n(P) + n(P') \implies n(P') = 28 - n(P)

so that

n(P'  \cup Q) = (28 - n(P)) + n(Q) - 2n(P) = 28 - 3n(P) + n(Q)

Now,

n(\xi) = 28 \implies n(P \cup Q) = 28 - 7 = 21

and by inclusion/exclusion,

n(P \cup Q) = n(P) + n(Q) - n(P \cap Q)

Decompose Q into the union of two disjoint sets:

Q = (P \cap Q) \cup (P' \cap Q)

Since they're disjoint,

n(Q) = n(P\cap Q) + n(P'\cap Q) \implies n(Q) = n(P\cap Q) + 2n(P)

\implies n(P \cup Q) = n(P) + (n(P\cap Q) + 2n(P)) - n(P \cap Q)

\implies 21 = 3n(P)

\implies n(P) = 7

From the Venn diagram, we see there are 3 elements unique to P - by the way, this is the set P \cap Q' - so n(P\cap Q) = 7-3 = 4, and it follows that

n(Q) = n(P\cap Q) + 2n(P) = 4 + 2\times7 = 18

Finally, we get for (a)

n(P' \cup Q) = 28 - 3n(P) + n(Q) = 28 - 3\times7 + 18 = \boxed{25}

For (b), we have by inclusion/exclusion that

n(P \cup Q') = n(P) + n(Q) - n(P \cap Q') = 7 + 18 - 3 = \boxed{22}

5 0
2 years ago
PLEASE HELP MEEEEEEEEEE
Alona [7]

Answer:

15

Step-by-step explanation:

<em>here's </em><em>your</em><em> solution</em>

<em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em>=</em><em>></em><em> </em><em>Both </em><em>the </em><em>traingle</em><em> </em><em>are </em><em>similar</em><em> </em><em>hence </em><em>,</em>

<em> </em><em> </em><em> </em><em> </em><em> </em><em>=</em><em>></em><em> </em><em>it's</em><em> </em><em>corresponding</em><em> </em><em>sides</em><em> </em><em>are </em><em>in </em><em>equal </em><em>ratio</em>

<em> </em><em> </em><em> </em><em> </em><em>=</em><em>></em><em> </em><em>so,</em><em>8</em><em>/</em><em>2</em><em>0</em><em> </em><em>=</em><em> </em><em>6</em><em>/</em><em>y </em>

<em> </em><em> </em><em> </em><em> </em><em> </em><em>=</em><em>></em><em> </em><em>8</em><em>y</em><em> </em><em>=</em><em> </em><em>2</em><em>0</em><em>*</em><em>6</em>

<em> </em><em> </em><em> </em><em> </em><em> </em><em>=</em><em>></em><em> </em><em>y=</em><em> </em><em>2</em><em>0</em><em>*</em><em>6</em><em>/</em><em>8</em>

<em> </em><em> </em><em> </em><em> </em><em> </em><em>=</em><em>></em><em> </em><em>y </em><em>=</em><em> </em><em>1</em><em>5</em>

<em> </em><em> </em><em> </em><em> </em><em>hope</em><em> it</em><em> helps</em>

4 0
3 years ago
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