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Anvisha [2.4K]
3 years ago
12

Solve for V in V=s 3square if S=4

Mathematics
1 answer:
Rainbow [258]3 years ago
5 0

Step-by-step explanation:

V = s 3 square where s = 4

V = 4(9)

V = 36

9 is the square of 3

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There are currently 3 people signed up for the debate club. The school will not recognize the club officially until it has more
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D because it does not have shaded, it’s not shaded so it does not include 2, and 3 and up people need to join the club still for it to be official
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Justin is training for a hamburger eating competition. He is eventually able to eat 15 hamburgers in 10 minutes. What is justin’
user100 [1]

Answer:

1.5 hamburgers per minute

Step-by-step explanation:

In 10 minutes, Justin can eat 15 burgers.

In 1 minute, Justin can eat 15/10 burgers.

15/10 = 1.5

7 0
3 years ago
Lines 3x-2y+7=0 and 6x+ay-18=0 is perpendicular. What is the value of a?
BlackZzzverrR [31]

Answer:

\boxed{\sf a = 9 }

Step-by-step explanation:

Two lines are given to us which are perpendicular to each other and we need to find out the value of a . The given equations are ,

\sf\longrightarrow 3x - 2y +7=0

\sf\longrightarrow 6x +ay -18 = 0

Step 1 : <u>Conver</u><u>t</u><u> </u><u>the </u><u>equations</u><u> in</u><u> </u><u>slope</u><u> intercept</u><u> form</u><u> </u><u>of</u><u> the</u><u> line</u><u> </u><u>.</u>

\sf\longrightarrow y = \dfrac{3x}{2} +\dfrac{ 7 }{2}

and ,

\sf\longrightarrow y = -\dfrac{6x }{a}+\dfrac{18}{a}

Step 2: <u>Find </u><u>the</u><u> </u><u>slope</u><u> of</u><u> the</u><u> </u><u>lines </u><u>:</u><u>-</u>

Now we know that the product of slope of two perpendicular lines is -1. Therefore , from Slope Intercept Form of the line we can say that the slope of first line is ,

\sf\longrightarrow Slope_1 = \dfrac{3}{2}

And the slope of the second line is ,

\sf\longrightarrow Slope_2 =\dfrac{-6}{a}

Step 3: <u>Multiply</u><u> </u><u>the </u><u>slopes </u><u>:</u><u>-</u><u> </u>

\sf\longrightarrow \dfrac{3}{2}\times \dfrac{-6}{a}= -1

Multiply ,

\sf\longrightarrow \dfrac{-9}{a}= -1

Multiply both sides by a ,

\sf\longrightarrow (-1)a = -9

Divide both sides by -1 ,

\sf\longrightarrow \boxed{\blue{\sf a = 9 }}

<u>Hence </u><u>the</u><u> </u><u>value</u><u> of</u><u> a</u><u> </u><u>is </u><u>9</u><u> </u><u>.</u>

8 0
3 years ago
Which equation can be solved to find one of the missing side lengths in the triangle?
tester [92]

Answer:

cos(60) = 12

Step-by-step explanation:

I don't understand the question, but that is the only logical answer choice.

6 0
3 years ago
PLEASE HELP ASAP NO LINKS
insens350 [35]

<u><em>function </em></u>: p(x) = 65 + 25(x)

for 3 sells

  • p(3) = 65 + 25(3)
  • p(3) = 140

for 10 sells

  • p(10) = 65 + 25(10)
  • p(10) = 315

So,

140 ≤ p(x) ≤ 315

8 0
2 years ago
Read 2 more answers
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