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3 years ago

If I have X/3 and that equals 5 what does X equal?

Mathematics

2 answers:

ArbitrLikvidat [17]3 years ago

5 0

If 3x5 is 15, then X=15

Alex777 [14]3 years ago

4 0

Answer:

you can plug in for variables, so if x = 3, then 4x = 12, because 4x = 4(3): this is the "substitution" property. ... If x + 2 = 10, then x + 2 + (–2) equals what, and why? ... to solve it, I'd have subtracted 2 from both sides, and simplified to get x = 8.

Step-by-step explanation:

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PLEASE ANSWER ILL GIEV BRAINLY At a picnic, 2 families share 3 submarine sandwiches. How much of a sandwich will each family get

n200080 [17]

Answer:

Step-by-step explanation:

it's kinda hmm alarming that this doesn't make sense to you. :/ how much money would 2 people get.. if the split 3 dollars evenly?

$1.50 each right?

so each family would get 1 1/2 sandwiches.. see how it's the same? :/

8 0

3 years ago

Read 2 more answers

Alex has 3 times as many pets as Roman. If they have 24 altogether ,how many do they have ?

Viefleur [7K]

A= 3R
R = A/3
24= A + R
24= 3R + R
24 = 4R
6= R
A= 18

Roman = 6
Alex = 18

6+18 = 24

5 0

3 years ago

Read 2 more answers

Which statement best describes what happens when k is changed from 2 to – 3

antoniya [11.8K]

Where are the statements

5 0

3 years ago

What is the slope in the table below

eduard

Answer:

<h2>The table does not show a linear function</h2>

Step-by-step explanation:

$\text{The formula of a slope:}\\\\m=\dfrac{y_2-y_1}{x_2-x_1}\\\\\text{From the table we have:}\\\\(5,\ 24),\ (10,\ 21),\ (15,\ 17),\ (20,\ 13)\\\\\text{Check}\\\\\dfrac{21-24}{10-5}=\dfrac{-3}{5}=-\dfrac{3}{5}\\\\\dfrac{17-21}{15-10}=\dfrac{-4}{5}=-\dfrac{4}{5}\\\\-\dfrac{3}{5}\neq-\dfrac{4}{5}$

3 0

3 years ago

Mathematical Statistics with Applications Homework Help

photoshop1234 [79]

7.37:

a. W follows a chi-squared distribution with 5 degrees of freedom. See theorem 7.2 from the same chapter, which says

$\displaystyle \sum_{i=1}^n\left(\frac{Y_i-\mu}{\sigma}\right)^2$

is chi-squared distributed with n d.f.. Here we have $\mu=0$ and $\sigma=1$ .

b. U follows a chi-squared distribution with 4 degrees of freedom. See theorem 7.3:

$\displaystyle \frac1{\sigma^2}\sum_{i=1}^n (Y_i-\overline Y)^2$

is chi-squared distributed with n - 1 d.f..

c. Y₆² is chi-square distributed for the same reason as W, but with d.f. = 1. The sum of chi-squared distributed random variables is itself chi-squared distributed, with d.f. equal to the sum of the individual random variables' d.f.s. Then U + Y₆² is chi-squared distributed with 5 + 1 = 6 degrees of freedom.

7.38:

a. Notice that

$\dfrac{\sqrt 5 Y_6}{\sqrt W} = \dfrac{Y_6}{\sqrt{\frac W5}}$

and see definition 7.2 for the t distribution. Since Y₆ is normally distributed with mean 0 and s.d. 1, it follows that this random variable is t distributed with 5 degrees of freedom.

b. Similar manipulation gives

$\dfrac{2Y_6}{\sqrt U} = \dfrac{\sqrt4 Y_6}{\sqrt U} = \dfrac{Y_6}{\sqrt{\frac U4}}$

so this r.v. is t distributed with 4 degrees of freedom.

4 0

3 years ago