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valentinak56 [21]
3 years ago
5

at what value of x does the graph of the following function f(x) have a vertical asymptote F(x)=1/x+2

Mathematics
2 answers:
Fiesta28 [93]3 years ago
5 0

Answer: -2

Step-by-step explanation: this is the correct answer on a.p.e.x.

JulijaS [17]3 years ago
4 0
Vertical asymptote means the equation is undefined at that point, or when the denominator is 0. Is the equation F(x)=1/x+2 or F(x)=1/(x+2)? Just set whatever's on the bottom equal to zero and solve for x.
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PLZ HELP WILL GIVE BRAINLIEST!!!!!
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8 0
2 years ago
Hello, how can I do this equation?
kompoz [17]
(9^x) - 3 = 2*3^x
(9^x) - 3 - (2*3^x) = (2*3^x) - (2*3^x)
(9^x) - (2*3^x) - 3 = 0
(3^2)^x - 2*(3^x) - 3 = 0
3^(2x) - 2*(3^x) - 3 = 0
3^(x*2) - 2*(3^x) - 3 = 0
(3^x)^2 - 2*(3^x) - 3 = 0
z^2 - 2*z - 3 = 0  ............ let z = 3^x
(z - 3)(z + 1) = 0

If z-3 = 0, then z = 3 when we isolate z
If z = 3, and z = 3^x, then
z = 3
3^x = 3
3^x = 3^1
x = 1
which is a solutin in terms of x

If z+1 = 0 then z = -1
If z = -1 and z = 3^x, then there are NO solutions for this part of the equation
The quantity 3^x is never negative no matter what the x value is

---------------------------------------------------------------

Answer: x = 1
4 0
3 years ago
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