All categories

3 years ago

The sum of 2 consecutive numbers is 69. What are the numbers?

Mathematics

1 answer:

Vaselesa [24]3 years ago

7 0

Answer:

Step-by-step explanation:

z - some integer

then the consecutive integer would be:

z+1, (or z-1)

the sum is 69 so:

z + z+1 = 96

2z = 68

z = 34

z+1 = 34 + 1 = 35

(or:

z + z-1 = 69

2z = 70

z = 35

z-1 = 35 - 1 = 34)

You might be interested in

What is an equation of the line that passes through point (5,-8) and is parallel to the line x+y=7

Igoryamba

Answer:

The line given is equal to y=-x+7 (Through rearranging)

To find the new line, we substitute the given coordinates (5,8) in the equation without the given y-intersect (+7):

-8=-5+c

c=-3

The line parallel to x+y=7 that passes through the point (5,-8) is y=-x-3

4 0

3 years ago

Question

ololo11 [35]

Answer:

correct experiment: viral culture test

Trial: (RCT) random control trial

It causes mild sickness or death

6 0

2 years ago

I would really appreciate some help on this.

8_murik_8 [283]

Answer:

1. terms: 4r, 2, -6, and 3r like terms: 2 and -6, 4r and 3r

2.terms: 5h^2, -3h^2, - 4h, 3h, 7 like terms: 5h^2 and -3h^2, - 4h and 3h

3. 3m + 6

4. 15b + 2

5. 3x + 9

Step-by-step explanation:

1. 4r + 2 - 6 +3r

terms: 4r, 2, -6, and 3r like terms: 2 and -6, 4r and 3r

2. 5h^2 - 3h^2 - 4h + 3h + 7

terms: 5h^2, -3h^2, - 4h, 3h, 7 like terms: 5h^2 and -3h^2, - 4h and 3h

3. 6m + 7 - 3m-1

3m + 6

4. 3(5b +2) - 4

15b + 6 - 4

15b + 2

5. 2x + 4 + 5 + x

3x + 9

5 0

3 years ago

Multiply the terms 3xyz and -5x²yz

Evgesh-ka [11]

Answer:

-15X^3y^2Z^2 is the answer

3 0

2 years ago

What are the zeros of the polynomial function f(x)=x^3-5x^2-6x ?

iren2701 [21]

Option C

The zeros of the polynomial function f(x) = x^3 - 5x^2 - 6x is x = 0 and x = -1 and x = 6

<h3><u>Solution:</u></h3>

Given that polynomial function is f(x) = x^3 - 5x^2 - 6x

We have to find the zeros of polynomial

To find zeros, equate the given polynomial function to 0. i.e f(x) = 0

$x^3 - 5x^2 - 6x = 0$

Taking "x" as common term,

$x(x^2 - 5x - 6) = 0$

Equating each term to zero, we get

$x=0 \text { and } x^{2}-5 x-6=0$

Thus one of the zeros of function is x = 0

Now let us solve $x^{2}-5 x-6=0$

We can rewrite -5x as -6x + x

$x^2 + x - 6x - 6 = 0$

Taking "x" as common from first two terms and -6 as common from next two terms

$x(x + 1) -6(x + 1) = 0$

Taking (x + 1) as common term,

(x + 1)(x - 6) = 0

x + 1 = 0 and x - 6 = 0

x = -1 and x = 6

Thus the zeros of given function is x = 0 and x = -1 and x = 6

3 0

3 years ago

Read 2 more answers