Question 8 -4(x+5) = 5(x-4)

Mathematics

1 answer:

stealth61 [152]3 years ago

4 0

Answer:

The answer to the question is 0 so x = 0.

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Which of the following graphs is described by the function below ?

const2013 [10]

Answer:

The point of interception of the graph and x axis are -2.366 and -0.634.

The only graph that satisfy this conditions is Graph A

Step-by-step explanation:

Given the equation;

$y = 2x^2 + 6x + 3\\$

at y = 0

$2x^2 + 6x + 3=0\\$

the roots of the quadratic equation (at y =0) can be calculated using the quadratic formula;

$x = \frac{-b\pm \sqrt{b^2 -4ac}}{2a}$

Using the quadratic equation to solve for the roots;

$x = \frac{-6\pm \sqrt{6^2 -4*2*3}}{2*2}\\x = \frac{-6\pm \sqrt{36 - 24}}{4}\\x = \frac{-6\pm \sqrt{12}}{4}\\so, we have \\x = -2.366\\or\\x = -0.634\\$

Therefore, the point of interception of the graph and x axis are -2.366 and -0.634.

The only graph that satisfy this conditions is Graph A

4 0

4 years ago

Need help fast will give brainiest

Elan Coil [88]

Answer:

$\text{1. }\triangle IJH\cong \triangle LKM, \\\text{2. }\triangle RST\cong \triangle YXZ, \\\text{3a. Reflexive Property}, \\\text{3b. ASA (Angle-Side-Angle)}$

Step-by-step explanation:

ASA (Angle-Side-Angle) is a proof of congruence that states if two triangles share two angles and the side between those two angles, the triangles are congruent. In problems 1 and 2, the following demonstrate this:

$\text{1. }\triangle IJH\cong \triangle LKM, \\\text{2. }\triangle RST\cong \triangle YXZ$

In problem 3, $\overline{IJ}\cong \overline{IJ}$ is known in geometry as the Reflexive Property. Because of this, the two triangles in the diagram for problem 3 now share two angles and the side between them, thus they are congruent from ASA (Angle-Side-Angle).