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patriot [66]
3 years ago
10

X = -135°, cos 2x = _______

Mathematics
1 answer:
Ket [755]3 years ago
4 0

Answer:

cos 2 x=1-sin^2 x

Step-by-step explanation:

x=-135°

cos 2x=cos (-270)=cos (-270+360)=cos 90=0

or cos 2x=1-2sin ²x=1-2(sin (-135))²

=1-2(-sin 135)²

=1-2(sin 135)²

=1-2(sin (180-45))²

=1-2(sin²45)

=1-2 (\frac{1}{\sqrt{2}})²

=1-1

=0

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Fill in the missing values to make the equations true.(a) log, 7 + log2 5 = log2음Х8(b) log, 8 - log, I = log,7(c) log, 4 = 2log,
Zielflug [23.3K]

(a).

Simplify the expression to obtain the value at missing place.

\begin{gathered} \log _27+\log _25=\log _2(7\cdot5) \\ =\log _235 \end{gathered}

Blank space: 35

(B).

Simplify the expression to obtain the value of missing place.

\log _9(\frac{8}{7})=\log _98-\log _97

Blank space : 7

(C)

Simplify the expression to obtain the value at missing place.

\begin{gathered} \log _74=\log _7(2)^2 \\ =2\log _72 \end{gathered}

Blank space: 2

8 0
1 year ago
Which statement is not true? X squared equals 100 if and only if X equals 10 orX equals -10. If X squared equal 100 then X equal
mamaluj [8]

Answer:

the second statement is not true

Step-by-step explanation:

If x squared equals 100, it doesn't mean necessarily that x is positive ten, since you can get 100 also by squaring the value (-10):

(-10)(-10)^{2} = (-10) x (-10) = 100

The second statement is ignoring the possibility of x being a negative ten which also gives 100 as answered when squared.

7 0
3 years ago
Find the 13th term in the following<br> arithmetic sequence :<br> 2, 10, 18, 26, ...
kondor19780726 [428]

Answer:

98

Step-by-step explanation:

This is an arithmetic sequence

The common difference is 10-2 =8

a1 = 2

an = a1+d(n-1)

an = 2+8(n-1)

we want the 13th term

a13 = 2 +8(13-1)

      =2+ 8*12

     = 2+96

     = 98

8 0
4 years ago
Read 2 more answers
What is the area of a triangle with base of 20 feet and a vertical height
VashaNatasha [74]

Answer:

A = 400 ft²

Step-by-step explanation:

The area (A) of a triangle is calculated as

A = \frac{1}{2} bh ( b is the base and h the vertical height ) , then

A = \frac{1}{2} × 20 × 40 = 10 × 40 = 400 ft²

8 0
3 years ago
Two sides of a triangle are perpendicular. If the two sides are 8cm and 6cm, calculate correct to the next degree, the smallest
Sati [7]

\boxed{Given:}

Length of the perpendicular ( opposite ) = 6 cm.

Length of the base ( adjacent ) = 8 cm.

\boxed{To\:find:}

The smallest angle of the triangle.

\boxed{Solution:}

\sf\purple{C.\:37°} ✅

\large\mathfrak{{\pmb{\underline{\red{Step-by-step\:explanation}}{\red{:}}}}}

In a right-angled triangle, if two sides are given, the measure of the unknown angle can be known.

Since the value of opposite and adjacent sides are given, we use the tangent formula.

tan θ = \frac{opposite}{adjacent}

✒ tan θ = \frac{6 \: cm}{8 \: cm}

✒ θ = {tan}^{ - 1} (0.75)

✒ θ = 36.9°

✒ θ = 37°

Now let us find the other unknown angle 'x'.

We know that,

Sum of angles of a triangle = 180°

✒ 37° + x + 90° = 180° (90° since it is a right-angled triangle)

✒ x + 127° = 180°

✒ x = 180° - 127°

✒ x = 53°

Therefore, the three angles of the triangle are 37°, 53° and 90°.

Hence, the smallest angle is 37°.

\huge{\textbf{\textsf{{\orange{My}}{\blue{st}}{\pink{iq}}{\purple{ue}}{\red{35}}{\green{♡}}}}}

7 0
3 years ago
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