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3 years ago

14

5 times x to the one fourth power

1 answer:

skelet666 [1.2K]3 years ago

3 0

Answer:

<em>5</em><em>x</em><em> </em><em>=</em><em> </em><em>1</em><em>/</em><em>4</em>

<em>X </em><em>=</em><em> </em><em>2</em><em>0</em><em> </em>

<em>hope</em><em> </em><em>it</em><em> </em><em>helps</em><em> </em><em>u</em><em> </em><em>if </em><em>yes</em><em> </em><em>then</em><em> </em><em>foll</em><em>ow</em><em> me</em>

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Which is greater 16.45 or 16.454

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16.454 is greater than 16.45.

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Ryan bought 3 books and a magazine . He paid $30 and relieved $5 change if the magazine cost twice as much as each book, find th

Montano1993 [528]

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KX equals X +4 find K7

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3 years ago

The product of 13 and the sum of a number an 15

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Answer:

(15+x) · 13

Step-by-step explanation:

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4 years ago

The table shows the hourly cookie sales by students in grades 7 and 8 at the school's annual bake sale. Grade 7 Grade 8 20 21 15

Naddika [18.5K]

Answer:

1. The interquartile range for the grade 7 data is 6.

2. The interquartile range for the grade 8 data is 6.

3. The difference of the medians of the two data sets is 2.

4. The difference is about 1/3 times the interquartile range of either data set.

Step-by-step explanation:

The hourly cookie sales by students in grades 7 and 8 at the school's annual bake sale is given by the following table.

Grade 7 Grade 8

20 21

15 29

30 14

24 19

18 24

21 25

The data set for grade 7 is

20, 15, 30, 24, 18, 21

Arrange the data in ascending order.

15, 18, 20, 21, 24, 30

Divide the data in four equal parts.

(15), 18, (20), (21), 24,( 30)

$Q_1=18, Median=\frac{20+21}{2}=20.5, Q_3=24$

The interquartile range for the grade 7 data is

$IQR=Q_3-Q_1=24-18=6$

Therefore the interquartile range for the grade 7 data is 6.

The data set for grade 8 is

21, 29, 14, 19, 24, 25

Arrange the data in ascending order.

14, 19, 21, 24, 25, 29

Divide the data in four equal parts.

(14), 19, (21), (24), 25, (29)

$Q_1=19, Median=\frac{21+24}{2}=22.5, Q_3=25$

The interquartile range for the grade 8 data is

$IQR=Q_3-Q_1=25-19=6$

Therefore the interquartile range for the grade 8 data is 6.

The difference of the medians of the two data sets is

$D=22.5-20.5=2$

Therefore the difference of the medians of the two data sets is 2.

Let the difference is about x times the interquartile range of either data set.

The IQR of each data is 6.

$D=x(IQR)$

$2=x(6)$

$\frac{2}{6}=x$

$\frac{1}{3}=x$

Therefore the difference is about 1/3 times the interquartile range of either data set.

8 0

3 years ago