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ololo11 [35]
3 years ago
12

A sample of n = 16 scores is selected from a population with LaTeX: \muμ = 80 with LaTeX: \sigmaσ = 20. On average, how much err

or would be expected between the sample mean and the population mean?
Mathematics
1 answer:
bagirrra123 [75]3 years ago
7 0

Answer:

5

Step-by-step explanation:

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

In this problem, we have that:

\mu = 80, \sigma = 20

On average, how much error would be expected between the sample mean and the population mean?

This is the standard deviation of the sample. We have that n = 16. So

s = \frac{\sigma}{\sqrt{n}} = \frac{20}{\sqrt{16}} = 5

The answer is 5.

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