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ryzh [129]
3 years ago
14

P(2, 2), Q(1, -3), R(-4, 2), S(-3, 7) Using the information above, answer the following questions. Find the length of RS Find th

e length of SP Find the length of PQ Find the length of RQ Use this information to determine if the quadrilateral a parallelogram.
Mathematics
1 answer:
Setler79 [48]3 years ago
8 0

Answer:

Yes the Quadrilateral is a Parallelogram.

Step-by-step explanation:

A parallelogram can be defined as a quadrilateral i.e a geometric shape with four sides that has opposite sides parallel and equal in length.

From the question, we are given the following points

P(2, 2), Q(1, -3), R(-4, 2), S(-3, 7)

Given points: (x1, y1) and (x2, y2)

The formula would be

√(x2 - x1)² +(y2 - y1)²

a) P(2, 2), Q(1, -3)

Length PQ = √(1 - 2)² +(-3 - 2)² = √-1² + -5² = √26

b) R(-4, 2), S(-3, 7)

Length RS = √(-3 - (-4))² + (7 - 2) ² = √ 1² + 5² = √26

c) R(-4, 2), Q(1, -3)

Length RQ = √(1 - (-4))² + (-3 - 2)² = √5² + 5² = √(25 + 25) = √50

d) S(-3, 7), P(2, 2)

Length SP = √(2 - (-3))² + (2 - 7)² = √5² +(-5)² = √(25 + 25) = √50

From the above solution, we can see that

Length PQ = Length RS

Length RQ = Length SP

This means the opposite sides are parallel and equal in length, hence it is a Parallelogram.

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MrMuchimi

Answer:

y =-\frac{1}{3}-2

Step-by-step explanation:

We are given;

  • A point (6, -4)
  • An equation of a line, 9x - 3y = 9

We are required to determine the equation a line passing through a point (6, -4) and perpendicular to the given line;

  • To answer the question we need to get the gradient of the given line first.
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y = 3x -3

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But; m₁ × m₂ = -1 (For perpendicular lines)

Therefore;

m₂ = -1 ÷ 3

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Therefore, the slope of the line in question is -1/3 and the line passes through (6, -4).

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\frac{y+4}{x-6}=\frac{-1}{3}

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3(y+4) = -1(x-6)\\3y + 12 = -x+6

In the form of slope-intercept, the equation will be;

3y = -x - 6\\y =-\frac{1}{3}-2

Thus, the equation of the line is;

y =-\frac{1}{3}-2

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