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victus00 [196]
3 years ago
12

Someone help me again

Mathematics
1 answer:
sasho [114]3 years ago
8 0
It will cost 24 dollars
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PLEASE HELP ME GUYS OR I WONT PASS <br>this calculus!!!!​
KonstantinChe [14]

Answer:

b.  \displaystyle \frac{1}{2}

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right<u> </u>

<u>Algebra I</u>

  • Functions
  • Function Notation
  • Exponential Rule [Rewrite]:                                                                              \displaystyle b^{-m} = \frac{1}{b^m}
  • Exponential Rule [Root Rewrite]:                                                                     \displaystyle \sqrt[n]{x} = x^{\frac{1}{n}}<u> </u>

<u>Calculus</u>

Derivatives

Derivative Notation

Basic Power Rule:

  • f(x) = cxⁿ
  • f’(x) = c·nxⁿ⁻¹

Derivative Rule [Chain Rule]:                                                                                       \displaystyle \frac{d}{dx}[f(g(x))] =f'(g(x)) \cdot g'(x)

Step-by-step explanation:

<u>Step 1: Define</u>

<em>Identify</em>

<em />\displaystyle H(x) = \sqrt[3]{F(x)}<em />

<em />

<u>Step 2: Differentiate</u>

  1. Rewrite function [Exponential Rule - Root Rewrite]:                                      \displaystyle H(x) = [F(x)]^\bigg{\frac{1}{3}}
  2. Chain Rule:                                                                                                        \displaystyle H'(x) = \frac{d}{dx} \bigg[ [F(x)]^\bigg{\frac{1}{3}} \bigg] \cdot \frac{d}{dx}[F(x)]
  3. Basic Power Rule:                                                                                             \displaystyle H'(x) = \frac{1}{3}[F(x)]^\bigg{\frac{1}{3} - 1} \cdot F'(x)
  4. Simplify:                                                                                                             \displaystyle H'(x) = \frac{F'(x)}{3}[F(x)]^\bigg{\frac{-2}{3}}
  5. Rewrite [Exponential Rule - Rewrite]:                                                              \displaystyle H'(x) = \frac{F'(x)}{3[F(x)]^\bigg{\frac{2}{3}}}

<u>Step 3: Evaluate</u>

  1. Substitute in <em>x</em> [Derivative]:                                                                              \displaystyle H'(5) = \frac{F'(5)}{3[F(5)]^\bigg{\frac{2}{3}}}
  2. Substitute in function values:                                                                          \displaystyle H'(5) = \frac{6}{3(8)^\bigg{\frac{2}{3}}}
  3. Exponents:                                                                                                        \displaystyle H'(5) = \frac{6}{3(4)}
  4. Multiply:                                                                                                             \displaystyle H'(5) = \frac{6}{12}
  5. Simplify:                                                                                                             \displaystyle H'(5) = \frac{1}{2}

Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit: Derivatives

Book: College Calculus 10e

5 0
3 years ago
A carton can hold 1000 unit cubes that measure 1 inch by 1 inch by 1 inch. Describe the dimensions of the carton using unit cube
navik [9.2K]
The dimensions of the carton are:

10 x 10 x 10 [inch OR unit cubes - it's the same since cubes' dimensions are 1 x 1 x 1 inch)

I attach the explanation below.

6 0
2 years ago
Could someone please show me how to figure this problem out?
elixir [45]
The baby blue whale weighs 30 pounds, since 120 divided by 40 is 30.
5 0
2 years ago
HELP PLEASE! Thank you
Lostsunrise [7]

Answer:

2000

Step-by-step explanation:

Hello,

A or C means 2 ways

and then a digit means 10 ways 0, 1, 2, 3, 4, 5, 6, 7, 8, 9

so in total we have 2*10*10*10 = 2000 possible codes

Hope this helps

5 0
3 years ago
What is the answer and work shown for 9r+r+7b+10+b+r+4n
ladessa [460]
Combine like terms
9r+r=10r^2
7b+b=8b^2
10+10r^2+8b^2+4n
7 0
2 years ago
Read 2 more answers
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