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Ket [755]
3 years ago
10

For question 3, is it right though? Thankss

Mathematics
1 answer:
pishuonlain [190]3 years ago
8 0

Yes it is correct, 7/12 is the equivalent to C. 7 divided by 12

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Needs help with questions i math
n200080 [17]

Answer:

what is the question

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
Find quadratic polynomial which best fits the function f(x)=e^x and x=0, in the sense that g(0)= f(0), and g'(0) = f'(0), and g"
Dmitriy789 [7]
Let g(x)=ax^2+bx+c. Then

\begin{cases}g(0)=c\\g'(0)=b\\g''(0)=2a\end{cases}

Meanwhile, since f(x)=e^x, you have f(0)=f'(0)=f''(0)=e^0=1.

It follows that a=\dfrac12, b=1, and c=1, so that the quadratic fit for f(x)=e^x that satisfies the given points is

g(x)=\dfrac12x^2+x+1

Note that this is just the second-order Taylor polynomial for e^x about x=0.
3 0
4 years ago
If two objects travel through space along two different curves, it’s often important to know whether they will collide. (Will a
galina1969 [7]

Answer:

<em>Both objects collide at t=3 in the point  <9,9,9></em>

Step-by-step explanation:

<em>Collision Of Moving Objects </em>

Two objects can describe different trajectories in the space. Those trajectories can intersect in one or more points but it doesn't mean they collide. Collision occurs if they are in the same position at the same time. If we know the positions as a function of time of each object, we could try so find if, for a given time, they are in the same position.

The positions of two object are given as

r1(t)=

r2(t)=

Let's find out if there is at least one value of t that makes both positions to be the same. We can try by equating one of the three coordinates and testing if the value of t make both have the same x,y,z coordinate. Let's try equating the x-components of both

t^2=4t-3

Rearranging

t^2-4t+3=0

Factoring

(t-1)(t-3)=0

We found two solutions

t=1,\ t=3

for t=1 the x-coordinates are

x1=t^2=1

x2=4t-3=1

For t=3

x1=t^2=9

x2=4t-3=9

Now we'll test both values in the y-coordinates

y1=7t-12

y2=t^2

For t=1

y1=-5

y2=1

Thus they don't collide at t=1. Let's try t=3

y1=7(3)-12=9

y2=3^2=9

Now let's try the z-coordinate for t=3

z1=t^2=9

z2=5t-6=9

Since the three coordinates match, we can say both objects collide at t=3 in the point  <9,9,9>

6 0
4 years ago
What is the sequence for g(1)=-29 g(n)=g(n-1)x(-4)
kupik [55]

Answer:

g(n) = -29×(-4)ⁿ⁻¹

Step-by-step explanation:

This the recursive formula of a sequence g :

g(1)=-29

g(n)=g(n-1)x(-4)

now ,we want to deduce the standard explicit formula of that sequence

It’s clear from the recursive formula (above) that  :

_The common ratio = -4

_the first term = -29

Then

the standard explicit formula is : g(n) = -29×(-4)ⁿ⁻¹

8 0
3 years ago
What is the length of CD? In this diagram, AABC ~ AEDC. 20-% c * 7 21​
d1i1m1o1n [39]

Answer:

\frac{BC}{DC}=\frac{AC}{EC}

\frac{20-x}{x} =\frac{21}{7}

\frac{20-x}{x} =3

20-x=3x

4x=20

x=5

So, CD=5

<u>OAmalOHopeO</u>

<u />

6 0
3 years ago
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