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iren2701 [21]
2 years ago
12

Please help with this paper!! asap please

Mathematics
1 answer:
neonofarm [45]2 years ago
7 0
1 is L
2 is N
3 is M

Look back at your notes if you have any.


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Lynna [10]

a=1, b =18

a=2, b = 9

a = 3 , b = 6

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3 years ago
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Can the sum of two mixed numbers be equal to 2? ​
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No it depends on the sum of the two numbers
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There are big spenders among University of Alabama football season ticket holders. This data set Roll Tide!! shows the dollar am
Bas_tet [7]

Using the z-distribution, as we have a proportion, the 95% confidence interval is (0.2316, 0.3112).

<h3>What is a confidence interval of proportions?</h3>

A confidence interval of proportions is given by:

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which:

  • \pi is the sample proportion.
  • z is the critical value.
  • n is the sample size.

In this problem, we have a 95% confidence level, hence\alpha = 0.95, z is the value of Z that has a p-value of \frac{1+0.95}{2} = 0.975, so the critical value is z = 1.96.

We also consider that 130 out of the 479 season ticket holders spent $1000 or more at the previous two home football games, hence:

n = 479, \pi = \frac{130}{479} = 0.2714

Hence the bounds of the interval are found as follows:

\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.2714 - 1.96\sqrt{\frac{0.2714(0.7286)}{479}} = 0.2316

\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.2714 + 1.96\sqrt{\frac{0.2714(0.7286)}{479}} = 0.3112

The 95% confidence interval is (0.2316, 0.3112).

More can be learned about the z-distribution at brainly.com/question/25890103

7 0
2 years ago
In the hyperbola graph,how do you find the domain and range?​
xxTIMURxx [149]

Step-by-step explanation:

<h2><em>y = ± 5⁄2 x</em></h2><h2><em>y = ± 5⁄2 xThe equation is the left half of the hyperbola. The domain is ( – ∞, – 1⁄5 ]. The range is ( – ∞, ∞ ). The vertical line test indicates that this is not the graph of a function.</em></h2>
3 0
3 years ago
Pleaseeeeeee help me​
alekssr [168]

Answer:

-56

Step-by-step explanation:

(6 ✕–8) – 8

–48–8

= –56

3 0
3 years ago
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