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3 years ago

Find the value of 16+ 6 ÷ 2.

Mathematics

2 answers:

Vanyuwa [196]3 years ago

6 0

Answer: 19

Step-by-step explanation: To simplify 16 + 6 ÷ 2, it's important to understand that based on the order of operations or <u><em>pemdas</em></u>, multiplication and division come before addition and subtraction.

So our first step here is to divide 6 by 2 which is 3 and we have 16 + 3 which is 19.

To summarize, use the following order of operations when simplifying.

Parentheses

Exponents

Multiplication/Division

Addition/Subtraction

If you take the first letter from each of these words,

you get P E M D A S or pemdas which you can use as an easy way to remember your order of operations.

aleksklad [387]3 years ago

3 0

Answer:

Step-by-step explanation:

Remember to follow PEMDAS.

PEMDAS is the order of operations, and is:

Parenthesis

Exponents (& roots)

Multiplication

Division

Addition

Subtraction

First, divide 6 with 2: 6/2 = 3

Next, add: 16 + 3 = 19

19 is your value.

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<h3>Simplifying Logarithms</h3>

From the question, we are to write the given logarithm expression as a sum or difference of logarithms

The given logarithm is

$log_{4 }6ab$

This can be written as

$log_{4 }6 \times a \times b$

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Thus,

$log_{4 }6 \times a \times b$ becomes

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This can be further simplified into

$log_{4 }3 \times 2 + log_{4 }a + log_{4 }b$

$log_{4 }3 + log_{4 }2 + log_{4 }a + log_{4 }b$

If desired, this can be further simplified into

$log_{4 }3 + log_{2^{2} }2 + log_{4 }a + log_{4 }b$

$log_{4 }3 + \frac{1}{2} log_{2}2 + log_{4 }a + log_{4 }b$

$log_{4 }3 + \frac{1}{2} (1)+ log_{4 }a + log_{4 }b$

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Hence, the logarithm written as a sum of logarithm and simplified as much as possible is $\frac{1}{2} +log_{4 }3 + log_{4 }a + log_{4 }b$

Learn more on Simplifying logarithms here: brainly.com/question/17851187

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