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4 years ago

Find the approximate area of the triangle.

Mathematics

2 answers:

Julli [10]4 years ago

7 0

Answer:

The area of triangle is 19.8 square units

Option B is correct.

Step-by-step explanation:

Given the triangle ABC in which

AB=6.8 units, BC=5.9 units and ∠B=99°

we have to find the area of triangle.

c=6.8 units and a=5.9 units

The area of triangle can be calculated as

$Area=\frac{1}{2}ac\sin \angle B$

$=\frac{1}{2}\times 5.9\times 6.8\times \sin 99^{\circ}$

$=20.06\times \sin 99^{\circ}=19.813\sim 19.8 units^2$

The area of triangle is 19.8 square units

Option B is correct.

kykrilka [37]4 years ago

6 0

Answer:

B. 19.8 square units

Step-by-step explanation:

For this geometry an appropriate formula for the area is ...

area = (1/2)·a·c·sin(B) = (1/2)·(5.9 units)·(6.8 units)·sin(99°) ≈ 19.8 units²

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4 years ago

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$y=25,700(0.85)^{x}$

Step-by-step explanation:

we know that

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4 years ago

Write the equation of the line through (2,3) and (-1,-12) in slope

Ksivusya [100]

Answer:

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Step-by-step explanation:

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= (-12 - 3) / (-1 - 2)

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3 years ago

Y = f(x) = 16x Find f(x) when x = 1/2

Alina [70]

Answer:

The answer depends on what the problem really is.

f(1/2) = 8

f(1/2) = 4

See below.

Step-by-step explanation:

This is the problem as it was posted:

y = f(x) = 16x

Let x = 1/2

y = f(1/2) = 16(1/2) = 8

Perhaps the problem is this:

$y = f(x) = 16^x$

If x is an exponent of 16 and not a factor, then the answer is:

$y = f(\frac{1}{2}) = 16^\frac{1}{2} = \sqrt{16} = 4$

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3 years ago