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2 years ago

Solve this equation with steps so I understand -16x^3+4x=0

1 answer:

5 0

<span>-16x^3+4x=0
-4x(4x^2 - 1) = 0
-4x(2x+1)(2x - 1) = 0 (factor using a^2 - b^2 = (a+b)(a-b))

-4x = 0; x =0
2x +1 = 0;x = -1/2
2x - 1 =0; x = 1/2

answer: x = 0, x = 1/2 and x = -1/2</span>

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Please help, What is the nth term rule of the quadratic sequence below?<br> -4,1,12,29,52,81,116

Evgesh-ka [11]

Answer:

29-12 is a 17 difference

52-29 is a 23 difference (adding 6 to the number 17)

81-52 is a 29 difference (adding 6 to the number 23)

116-81 is a 35 difference (adding 6 to the number 29)

Step-by-step explanation:

7 0

2 years ago

Danielle makes the claim that when the polynomial x^2-3x-10 is divided by x-5, the remainder is 0. Use what you have learned abo

Mumz [18]

Answer:

<h3>Daniel is correct</h3>

Step-by-step explanation:

Given the polynomial P(x) = x^2-3x-10

To check that the remainder is zero if divided by x - 5, we will first have to equate x - 5 to zero and get x;

x - 5 = 0

x = 5

Then find P(5)

P(5) = 5^2 - 3(5) - 10

P(5) = 25 - 15 - 10

P(5) = 25-25

P(5) = 0

<em>This shows that x - 5 is a factor of the polynomial since P(5) gave us zero according to the factor theorem</em>

7 0

2 years ago

Hi guys . pls help me with this

daser333 [38]

Step-by-step explanation:

The upstream speed is S / t₁, and the downstream speed is S / t₂.

If we say f is the speed of the fish in calm water, and r is the speed of the river, then:

f − r = S / t₁

f + r = S / t₂

If we say T is the time it takes to cross the river, then the speed perpendicular to the river is ℓ/T, the speed parallel to the river is r, and the overall speed is f.

Using Pythagorean theorem:

f² = (ℓ/T)² + r²

f² − r² = (ℓ/T)²

(f − r) (f + r) = (ℓ/T)²

(S / t₁) (S / t₂) = (ℓ/T)²

S² / (t₁ t₂) = (ℓ/T)²

(t₁ t₂) / S² = (T/ℓ)²

√(t₁ t₂) / S = T/ℓ

T = ℓ√(t₁ t₂) / S

6 0

2 years ago

Creating and solving formulas for geometric series:mastery test

Levart [38]

Answer:

D. $y = 5\cdot \Sigma_{i=0}^{4} \left(\frac{1}{3} \right)^{i}$

Step-by-step explanation:

Let be $y = \Sigma_{i = 0}^{4} \left[5\cdot \left(\frac{1}{3} \right)^{i}\right]$ . To find the equivalent expression we must use the following property:

$y = c\cdot \Sigma_{i = 0}^{n} p(x) = \Sigma_{i=0}^{n} [c\cdot p(x)]$ (1)

Based on this fact, we find the following equivalence:

$y = 5\cdot \Sigma_{i=0}^{4} \left(\frac{1}{3} \right)^{i}$

Hence, the correct answer is D.

6 0

2 years ago

If the relative frequency of a train being late is 0.15 how often could you expect the train to be late in 100 days?

neonofarm [45]

(100)= 0.25*100=15 times.

<span>SO, the train will be late 15 times in 100 days.

Hope i helped:P </span>

7 0

2 years ago