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Sidana [21]
4 years ago
15

Ordered pairs that satisfy y=x^2+1

Mathematics
1 answer:
-BARSIC- [3]4 years ago
5 0
Using an ordered pair is a way of graphing a linear equation on a coordinate plane.
{(-1, 2), (0, 1), (1, 2), (4, 5)}.
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Please help me! :)
Eva8 [605]

y = - \frac{4}{3} x - 3

the equation of a line in ' slope intercept form ' is

y = mx + c

where m is the slope and c the y-intercept

here m = - \frac{4}{3} and c = - 3

thus y = -  \frac{4}{3}  x - 3 is the slope- intercept equation

3 0
4 years ago
Due in 10 minutes please help !! ASAP Erin buys 2 packs of potatoes costing £2 each, 3 packs of carrots for £3 per pack, and 3 t
lions [1.4K]

2(2) + 3(3) =

4 + 9 = 13

I don't know what 90p means but basically, u have to multiply that by 3 and add it to our current total which is 13.

Then, u substract the total cost from the 20 and you should get the change.

6 0
3 years ago
Simplify cubed 5 -10/27
MAXImum [283]

The correct answer for the given expression is 99.22.

<h3>What is an expression?</h3>

Expression in maths is defined as the collection of the numbers variables and functions by using signs like addition, subtraction, multiplication and division

The expression will be solved as:-

E = ({5 -\dfrac{10}{27}})^3

E = (\dfrac{135-10}{27})^3

E =\dfrac{125}{27}^3

E = 99.22

Therefore the correct answer for the given expression is 99.22.

To know more about Expression follow

brainly.com/question/723406

#SPJ1

4 0
2 years ago
Find the missing number so that the equations slope is 3/4.
taurus [48]

-3x+\boxed{?}y=-8\implies \boxed{?}y=3x-8\implies y = \cfrac{3x-8}{\boxed{?}} \\\\\\ y = \cfrac{3x-8}{4}\implies y = \stackrel{\stackrel{m}{\downarrow }}{\cfrac{3}{4}} x-2\qquad \impliedby \begin{array}{|c|ll} \cline{1-1} slope-intercept~form\\ \cline{1-1} \\ y=\underset{y-intercept}{\stackrel{slope\qquad }{\stackrel{\downarrow }{m}x+\underset{\uparrow }{b}}} \\\\ \cline{1-1} \end{array}

5 0
2 years ago
5. The gradient of the tangent line to the graph of f(x)= 2x^2 + kx - 3 at x = -1 is 1. Find the value of k
Trava [24]

The gradient of the tangent line to y(x) at (c,y(c)) is given by the value of the derivative at x=c. We have

f(x)=2x^2+kx-3\implies f'(x)=4x+k

We're told that f'(-1)=1. Then

1=4(-1)+k\implies k=5

4 0
4 years ago
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