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densk [106]
3 years ago
12

What is the y-intercept of a line that has a slope of One-fourth and passes through point (8, 3)?

Mathematics
2 answers:
kondor19780726 [428]3 years ago
6 0

Answer:

y-intercept is (0, 1)

Step-by-step explanation:

vichka [17]3 years ago
5 0

Answer:

y-intercept is (0, 1)

Step-by-step explanation:

The slope-intercept form: y = mx + b

m - a slope

b - y-intercept

We have a slope m = 1/4. Substitute: y = 1/4 x + b

We know, the line passes through point (8, 3) → x = 8, y = 3.

Put the values of x and y to the equation of the line:

1/4 · 8 + b = 3

2 + b = 3 |-2

b = 1

Answer: y-intercept is (0, 1)

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If g (x) = 1/x then [g (x+h) - g (x)] /h
lys-0071 [83]

Answer:

\dfrac{-1}{x(x+h)}, h\ne 0

Step-by-step explanation:

If g(x) = \dfrac{1}{x}, then g(x+h) = \dfrac{1}{x+h}. It follows that

  \begin{aligned} \\\frac{g(x+h)-g(x)}{h} &= \frac{1}{h} \cdot [g(x+h) - g(x)] \\&= \frac{1}{h} \left( \frac{1}{x+h} - \frac{1}{x} \right)\end{aligned}

Technically we are done, but some more simplification can be made. We can get a common denominator between 1/(x+h) and 1/x.

  \begin{aligned} \\\frac{g(x+h)-g(x)}{h} &= \frac{1}{h} \left( \frac{1}{x+h} - \frac{1}{x} \right)\\&=\frac{1}{h} \left(\frac{x}{x(x+h)} - \frac{x+h}{x(x+h)} \right) \\ &=\frac{1}{h} \left(\frac{x-(x+h)}{x(x+h)}\right) \\ &=\frac{1}{h} \left(\frac{x-x-h}{x(x+h)}\right) \\ &=\frac{1}{h} \left(\frac{-h}{x(x+h)}\right) \end{aligned}

Now we can cancel the h in the numerator and denominator under the assumption that h is not 0.

  = \dfrac{-1}{x(x+h)}, h\ne 0

5 0
3 years ago
What is the solution to 8 + 9p = 9p - 7?
Norma-Jean [14]

Answer:

15=0 not a real number

Step-by-step explanation:

8+9p=9p-7  

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15+9p=9p

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4 0
3 years ago
Read 2 more answers
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valina [46]

Answer:

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Step-by-step explanation:

8 0
2 years ago
Is this answer correct?
slavikrds [6]
NO. Sine is opposite/hypotenuse, so the answer should be 24/25
4 0
3 years ago
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