1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
iren [92.7K]
2 years ago
10

15. How many values are in the data set whose histogram is shown below?

Mathematics
1 answer:
Orlov [11]2 years ago
8 0

The total values in the dataset is 24 values

From the given histogram, to get the number of values in the dataset, we will have to trace each bar to the y-axis and then take the sum.

  • For the black bar, the total values of the dataset will be 11 + 2 = 13
  • For the white bar, the value of the data st will be 3
  • For the grey bar, the total values of the dataset will be 1 + 2 = 3
  • For the ask bar,  the total values of the dataset will be 2 + 3 = 5

The total values of the dataset = 13 + 3 + 3 + 5

The total values of the dataset = 24 values

Hence the total values in the dataset is 24 values

Learn more on histogram here: brainly.com/question/9388601

You might be interested in
What is the volume of the right prism?
Bess [88]
The answer would be B as half of 6 is 3 and 3 x 5 is 15 , 15 x 10 is 150 :)<span />
5 0
2 years ago
Read 2 more answers
The mean of a population is 74 and the standard deviation is 15. The shape of the population is unknown. Determine the probabili
Lena [83]

Answer:

a) 0.0548 = 5.48% probability of a random sample of size 36 yielding a sample mean of 78 or more.

b) 0.9858 = 98.58% probability of a random sample of size 150 yielding a sample mean of between 71 and 77.

c) 0.5793 = 57.93% probability of a random sample of size 219 yielding a sample mean of less than 74.2

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

The mean of a population is 74 and the standard deviation is 15.

This means that \mu = 74, \sigma = 15

Question a:

Sample of 36 means that n = 36, s = \frac{15}{\sqrt{36}} = 2.5

This probability is 1 subtracted by the pvalue of Z when X = 78. So

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{78 - 74}{2.5}

Z = 1.6

Z = 1.6 has a pvalue of 0.9452

1 - 0.9452 = 0.0548

0.0548 = 5.48% probability of a random sample of size 36 yielding a sample mean of 78 or more.

Question b:

Sample of 150 means that n = 150, s = \frac{15}{\sqrt{150}} = 1.2247

This probability is the pvalue of Z when X = 77 subtracted by the pvalue of Z when X = 71. So

X = 77

Z = \frac{X - \mu}{s}

Z = \frac{77 - 74}{1.2274}

Z = 2.45

Z = 2.45 has a pvalue of 0.9929

X = 71

Z = \frac{X - \mu}{s}

Z = \frac{71 - 74}{1.2274}

Z = -2.45

Z = -2.45 has a pvalue of 0.0071

0.9929 - 0.0071 = 0.9858

0.9858 = 98.58% probability of a random sample of size 150 yielding a sample mean of between 71 and 77.

c. A random sample of size 219 yielding a sample mean of less than 74.2

Sample size of 219 means that n = 219, s = \frac{15}{\sqrt{219}} = 1.0136

This probability is the pvalue of Z when X = 74.2. So

Z = \frac{X - \mu}{s}

Z = \frac{74.2 - 74}{1.0136}

Z = 0.2

Z = 0.2 has a pvalue of 0.5793

0.5793 = 57.93% probability of a random sample of size 219 yielding a sample mean of less than 74.2

5 0
3 years ago
If the surface of the water is at an elevation 0 meters, which person is located at an elevation
Eva8 [605]
The correct answer is that noa is located at an elevation
5 0
3 years ago
When solving negative one over five(x − 25) = 7, what is the correct sequence of operations?
Rufina [12.5K]
Add 25 to both sides x-25 +25 =7 +25
x =32 
7 0
3 years ago
What is 39/40 as a decimal?
Cerrena [4.2K]
39/40 as a decimal is 0.975
4 0
3 years ago
Read 2 more answers
Other questions:
  • I need all the answers I suck at this
    12·1 answer
  • 8x-6y=-18 <br>8x+7y=9<br>what does y equals
    6·1 answer
  • 5x2 this answer is for my brother only my next answer will be everyone's
    8·2 answers
  • Change this number from standard notation to scientific notation. 22.98504
    7·1 answer
  • What a division problem that equals 17
    10·2 answers
  • Each class at Greenville school has 22 children enrolled.the school has 24 classes how many children are enrolled at Greenville
    6·2 answers
  • Sandra has $60 in a savings account. The interest rate is 5%, compounded annually.
    6·1 answer
  • I need help with this problem <br><br> Someone explain this to me
    9·1 answer
  • HELP PLEASE ASAP!!! I NEED HELP
    8·1 answer
  • Urgent help wanted/ needed
    8·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!