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Stella [2.4K]
3 years ago
6

In Mary's video game, she receives a treasure box for completing a mission. Each treasure box gives Mary a special item. Every t

reasure box has a 52% chance
of having a coin, a 22% chance of having a potion, and a 26% chance of having a gem.

Mary wants to simulate what could happen for the next ten treasure boxes.

Let 1 to 52 represent a treasure box having a coin, 53 to 74 a potion, and 75 to 100 a gem.
A random whole number from 1 to 100 is generated for each simulated treasure box.

Here is Mary's simulation.
(Go to the Photo at the top)

In the simulation, which item (coin, potion, or gem) was in each treasure box?

(a) Treasure box 4:
(b) Treasure box 5:
(c) Treasure box 6:​

Mathematics
2 answers:
Hunter-Best [27]3 years ago
6 0

Answer:4 5 6

Step-by-step explanation:

nikitadnepr [17]3 years ago
5 0

Answer:

Treasure box 4: A gem

Treasure box 5: A coin

Treasure box 6: A potion

Step-by-step explanation:

89 is in between the two numbers 75-100

47 is in between the two numbers 1-52

and

74 is in between the two numbers 53-74

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coldgirl [10]

Answer:

0.30

Step-by-step explanation:

Probability of stopping at first signal = 0.36 ;

P(stop 1) = P(x) = 0.36

Probability of stopping at second signal = 0.54;

P(stop 2) = P(y) = 0.54

Probability of stopping at atleast one of the two signals:

P(x U y) = 0.6

Stopping at both signals :

P(xny) = p(x) + p(y) - p(xUy)

P(xny) = 0.36 + 0.54 - 0.6

P(xny) = 0.3

Stopping at x but not y

P(x n y') = P(x) - P(xny) = 0.36 - 0.3 = 0.06

Stopping at y but not x

P(y n x') = P(y) - P(xny) = 0.54 - 0.3 = 0.24

Probability of stopping at exactly 1 signal :

P(x n y') or P(y n x') = 0.06 + 0.24 = 0.30

8 0
3 years ago
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Travka [436]

Answer:

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Step-by-step explanation:

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5 0
3 years ago
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g100num [7]

Answer:

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7 0
3 years ago
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Compound interest In Exercise,$3000 is invested in an account at interest rate r,compounded continuously.Find the time required
xenn [34]

Answer:

(a) 8.15

(b) 12.92

Step-by-step explanation:

Given: P = $3000, r = 0.085

                A = Pe^{rt}

Where

A is the Amount

P is the Principal

r is the rate

t is the time

(a) For the amount to double, A = 2 × P

               A = 2 × $3000

               A = $6000

               6000 = 3000e^{0.085t}

               \frac{6000}{3000} = e^{0.085t}

               2 = e^{0.085t}

Take log_{e} of both sides

               log_{e}2 = log_{e}e^{0.085t}

But log_{e}e = 1

            ∴ ln2 = 0.085t

               t = \frac{ln2}{0.085}

               t = \frac{0.693}{0.085}

               t = 8.15

(b) For the amount to double, A = 3 × P

               A = 3 × $3000

               A = $9000

               9000 = 3000e^{0.085t}

               \frac{9000}{3000} = e^{0.085t}

               3 = e^{0.085t}

Take log_{e} of both sides

               log_{e}3 = log_{e}e^{0.085t}

But log_{e}e = 1

            ∴ ln3 = 0.085t

               t = \frac{ln3}{0.085}

               t = \frac{1.0986}{0.085}

               t = 12.92

5 0
3 years ago
8×(30+2)=(8×_)+(8×2)
irinina [24]
Using the distributive property, a(b+ c) = ab + ac. In this case, b is 30, so the blank is 30.
6 0
4 years ago
Read 2 more answers
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