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4 years ago

Which behavior of light makes it possible for you to see a spectrum of colors in a spray of water on a sunny day? diffusion

Physics

2 answers:

kramer4 years ago

7 0

The answer is refraction?

Ludmilka [50]4 years ago

6 0

The behavior of light makes it possible for you to see a spectrum of colors in a spray of water on a sunny day is refraction. The refractive index of a medium is dependent on the wavelength and hence light of different wavelength undergo refraction by different angle which causes the splitting of light beam in different color.

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Solve for variable in each figure below

Karolina [17]

Since this is definitely a RIGHT triangle (the little square in the corner),
the hypotenuse is 15, 'h' is the side opposite the 38-degree angle, and

sin(38°) = h / 15

Multiply each side by 15: h = 15 sin(38°)

= 15 (0.616)

h = 9.235

8 0

3 years ago

A woman weighs 649 N. What is her mass?

solong [7]

G=mg

649=10m

m=64,9kg

if we consider the gravitational acceleration 10m/s^2

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3 years ago

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A conservative force on a particle moving along the x axis is given by F = (3x^2-2x)i. Which of the following is a potential tha

ANTONII [103]

pck u

report me if you can

$tex]\purple{\rule{45pt}{7pt}}\blue{\rule{45pt}{999999pt}}$

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2 years ago

The fastest time ever run at Pikes Peak is 7:57. That’s way too long. If we removed all the curves, making a straight line from

anygoal [31]

Answer: 271.4 s

Explanation:

We are told the top speed (maximum speed) $V_{max}$ the car has is:

$V_{max}=203 mph=90.74 m/s$ taking into account $1 mile=1609.34 m$

And the car's average acceleration $a_{ave}$ is:

$a_{ave}=0.091 g=2.93 ft/s^{2}=0.89 m/s^{2}$

Since:

$a_{ave}=\frac{V_{f}-V_{o}}{\Delta t}$ (1)

Where:

$V_{f}=V_{max}=90.74 m/s$ is the car's final speed (top speed)

$V_{o}=0 m/s$ because it starts from rest

$\Delta t$ is the time it takes to reach the top speed

Finding this time:

$\Delta t=\frac{V_{f}-V_{o}}{a_{ave}}$ (2)

$\Delta t=\frac{90.74 m/s - 0 m/s}{0.89 m/s^{2}}$ (3)

$\Delta t=t_{1}=101.95 s$ (4)

Now we have to find the distance $d$ the car traveled at this maximum speed with the following equation:

$V_{f}^{2}=V_{o}^{2} + 2a_{ave} d$ (5)

Isolating $d$ :

$d=\frac{V_{f}^{2}}{2a_{ave}}$ (6)

$d=\frac{(90.74 m/s)^{2}}{2(0.89 m/s^{2})}$ (7)

$d=4625.70 m$ (8)

On the other hand, we know the total distance $D$ traveled by the car is:

$D=12.42 miles = 19988.052 m$

Hence the remaining distance is:

$d_{remain}=D-d=19988.052 m - 4625.70 m$ (9)

$d_{remain}=15362.35 m$ (10)

So, we can calculate the time $t_{2}$ it took to this car to travel this remaining distance $d_{remain}$ at its top speed $V_{max}$ , with the following equation: