Answer:
Sarah is right
Explanation:
This is an exercise that differentiates between scalars and vectors.
A scalar is a number, instead a vector is a number that represents the module in addition to direction and sense.
In this case, the distance (scalar) traveled is a number, which is why it is worth 1500m, but the displacement is a vector and since the point where it leaves is the same point where the vector's modulus arrives is zero, so the DISPLACEMENT VECTOR is zero
consequently Sarah is right
The movement of the tectonic plates is caused by convection currents in Earth´s mantle.
Answer: A) convection currents in Earth´s mantle.
Answer:
Explanation:
To find Sammy's course you have to add the two velocities (vectors), 18 mph 327º and 4 mph 60º.
To add the two vectors analytically you decompose each vector into their vertical and horizontal components.
<u>1. 18 mph 327º</u>
- Horizontal component: 18 mph × cos (327º) = 15.10 mph
- Vertical component: 18 mph × sin (327º) = - 9.80 mph
<u>2. 4 mph 60º</u>
- Horizontal component: 4 mph × cos (60º) = 2.00 mph
- Vertical component: 4 mph × sin (60º) = 3.46 mph
<u>3. Addition:</u>
You add the corresponding components:
To find the magnitude use Pythagorean theorem:
<u>4. Direction:</u>
Use the tangent ratio:
Find the inverse:
Answer:
10 gram gold is added
Explanation:
given data
pure gold = (24/24)
added = 15 grams
gold = 14 K ( 14/24)
gold = 18 K ( 18/24)
to find out
How much pure gold added
solution
we know here that when we add gold to get 20 K gold or 22K
so we added here 15 gram 14 K
we consider here m is pure gold added
so by composition here
we get
15 (14K) + m ( 24 K) = ( 15 + m ) (18) ...................1
solve it and find m
m = 10
so 10 gram gold is added
Given Information:
Current in loop = I = 62 A
Magnitude of magnetic field = B = 1.20x10⁻⁴ T
Required Information:
Radius of the circular loop = r = ?
Answer:
Radius of the circular loop = 0.324 m
Explanation:
In a circular loop of wire with radius r and carrying a current I induces a magnetic field B which is given by
B = μ₀I/2r
Please note that for an infinitely straight long wire we use 2πr whereas for circular loop we use 2r
Where μ₀= 4πx10⁻⁷ is the permeability of free space
Re-arranging the equation yields
r = μ₀I/2B
r = 4πx10⁻⁷*62/2*1.20x10⁻⁴
r = 0.324 m
Therefore, the radius of this circular loop is 0.324 m
